A new fixed point theorem in a cone is applied to obtain the existence of positive
solutions of some fourth-order beam equation boundary value problems with dependence
on the first-order derivative 

where
is continuous.
1. Introduction
It is well known that beam is one of the basic structures in architecture. It is greatly used in the designing of bridge and construction. Recently, scientists bring forward the theory of combined beams. That is to say, we can bind up some stratified structure copings into one global combined beam with rock bolts. The deformations of an elastic beam in equilibrium state, whose two ends are simply supported, can be described by following equation of deflection curve:
(11)where
is Yang's modulus constant,
is moment of inertia with respect to
axes, determined completely by the beam's shape cross-section. Specially,
if the cross-section is a rectangle with a height of
and a width of
Also,
is loading at
. If the loading of beam considered is in relation to deflection and rate of change
of deflection, we need to research the more general equation
(12)According to the forms of supporting, various boundary conditions should be considered. Solving corresponding boundary value problems, one can obtain the expression of deflection curve. It is the key in design of constants of beams and rock bolts.
Owing to its importance in physics and engineering, the existence of solutions to this problem has been studied by many authors, see [1–10]. However, in practice, only its positive solution is significant. In [1, 9, 11, 12], Aftabizadeh, Del Pino and Manásevich, Gupta, and Pao showed the existence of positive solution for
(13)under some growth conditions of
and a nonresonance condition involving a two-parameter linear eigenvalue problem.
All of these results are based on the Leray-Schauder continuation method and topological
degree.
The lower and upper solution method has been studied for the fourth-order problem by several authors [2, 3, 7, 8, 13, 14]. However, all of these authors consider only an equation of the form
(14)with diverse kind of boundary conditions. In [10], Ehme et al. gave some sufficient conditions for the existence of a solution of
(15)with some quite general nonlinear boundary conditions by using the lower and upper solution method. The conditions assume the existence of a strong upper and lower solution pair.
Recently, Krasnosel'skii's fixed point theorem in a cone has much application in studying the existence and multiplicity of positive solutions for differential equation boundary value problems, see [3, 6]. With this fixed point theorem, Bai and Wang [6] discussed the existence, uniqueness, multiplicity, and infinitely many positive solutions for the equation of the form
(16)where
is a constant.
In this paper, via a new fixed point theorem in a cone and concavity of function, we show the existence of positive solutions for the following problem:
(17)where
is continuous.
We point out that positive solutions of (1.7) are concave and this concavity provides lower bounds on positive concave functions of their maximum, which can be used in defining a cone on which a positive operator is defined, to which a new fixed point theorem in a cone due to Bai and Ge [5] can be applied to obtain positive solutions.
2. Fixed Point Theorem in a Cone
Let
be a Banach space and
a cone. Suppose
are two continuous nonnegative functionals satisfying
(21)where
are two positive constants.
Lemma 2.1 (see [5]).
Let
are constants and
(22)are two open subsets in
such that
. In addition, let
(23)Assume
is a completely continuous operator satisfying






then
has at least one fixed point in 
3. Existence of Positive Solutions
In this section, we are concerned with the existence of positive solutions for the fourth-order two-point boundary value problem (1.7).
Let
with
be a Banach space,
a cone. Define functionals
(31)then
are two continuous nonnegative functionals such that
(32)and (2.1) hold.
Denote by
Green's function for boundary value problem
(33)Then
, for
, and
(34)Let
(35)However, (1.7) has a solution
if and only if
solves the operator equation
(36)It is well know that
is completely continuous.
Theorem 3.1.
Suppose there are four constants
such that
and the following assumptions hold:




Then, (1.7) has at least one positive solution
such that
(37)Proof.
Let
(38)be two bounded open subsets in
. In addition, let
(39)For
, by
, there is
(310)For
, because
, so
, that is to say
concave on
, it follows that
(311)Combined with
and
, for
, there is
(312)For
, by
, there is
(313)For
, by
, there is
(314)Now, Lemma 2.1 implies there exists
such that
, namely, (1.7) has at least one positive solution
such that
(315)that is,
(316)The proof is complete.
Theorem 3.2.
Suppose there are five constants
such that
and the following assumptions hold






Then, (1.7) has at least one positive solution
such that
(317)Proof.
We just need notice the following difference to the proof of Theorem 3.1.
For
, the concavity of
implies that
for
. By
, there is
(318)For
, by
, there is
(319)The rest of the proof is similar to Theorem 3.1 and the proof is complete.
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