We use a fixed point theorem in a cone to obtain the existence of positive solutions
of the differential equation,
,
, with some suitable boundary conditions, where
is a parameter.
1. Introduction
We consider the existence of positive solutions of the following two-point boundary value problem:
(BVPx3bb)where
and
are nonnegative constants, and
.
In the last thirty years, there are many mathematician considered the boundary value
problem (BVPλ) with
, see, for example, Chu et al. [1], Chu et al. [2], Chu and Zhau [3], Chu and Jiang [4], Coffman and Marcus [5], Cohen and Keller [6], Erbe [7], Erbe et al. [8], Erbe and Wang [9], Guo and Lakshmikantham [10], Iffland [11], Njoku and Zanolin [12], Santanilla [13].
In 1993, Wong [14] showed the following excellent result.
Theorem 1 A (see [14]).
Assume that
(11)is an increasing function with respect to
. If there exists a constant
such that
(12)where
for
, then, there exists
such that the boundary value problem (BVPλ) with
has a positive solution in
for
, while there is no such solution for
in which 
Seeing such facts, we cannot but ask "whether or not we can obtain a similar conclusion for the boundary value problem (BVPλ)." We give a confirm answer to the question.
First, We observe the following statements.
(1)Let
(13)on
, then
is the Green's function of the differential equation
in
with respect to the boundary value condition
.
(2)
, is a cone in the Banach space with
.
In order to discuss our main result, we need the follo wing useful lemmas which due to Lian et al. [15] and Guo and Lakshmikantham [10], respectively.
Lemma 1 B (see [10]).
Suppose that
be defined as in
. Then, we have the following results.

for
and
)

for
and
)
Lemma 1 C (see [10, Lemmas
and
]).
Let
be a real Banach space, and let
be a cone. Assume that
and
is completely continuous. Then
(1)
if
(14)(2)
where
is the fixed point index of a compact map
, such that
for
, with respect to
.
2. Main Results
Now, we can state and prove our main result.
Theorem 2.1.
Suppose that there exist two distinct positive constants
,
and a function
with
and
such that
(21)
(22)Then (BVPλ) has a positive solution
with
between
and
if
(23)where
(24)Proof.
It is clear that (BVPλ) has a solution
if, and only if,
is the solution of the operator equation
(25)It follows from the definition of
in our observation
and Lemma B that
(26)Hence,
, which implies
. Furthermore, it is easy to check that
is completely continuous. If there exists a
such that
, then we obtain the desired result. Thus, we may assume that
(27)where
and
. We now separate the rest proof into the following three steps.
Step 1.
It follows from the definitions of
and
that, for
,
(28)which implies
(29)Hence, by (2.5),
(210)which implies
(211)Hence
(212)We now claim that
(213)In fact, if there exist
and
such that
then, by (2.11),
(214)which gives a contradiction. This proves that (2.13) holds. Thus, by Lemma C,
(215)Step 2.
First, we claim that
(216)Suppose to the contrary that there exist
and
such that
(217)It is clear that (2.17) is equivalent to
(218)Since
and
it follows that there exists a
such that
(219)Let
(220)Then
. From
on
, we see that
on
on
and
on
. It follows from
(221)and
on
that
(222)Hence,
(223)Thus
(224)This contradiction implies
(225)Therefore, by Lemma C,
(226)Step 3.
It follows from Steps (1) and (2) and the property of the fixed point index (see,
for example, [10, Theorem
]) that the proof is complete.
Remark 2.2.
It follows from the conclusion of Theorem 2.1 that the positive constant
and nonnegative function
satisfy
(227)There are many functions
and positive constants
satisfying (2.27). For example, Suppose that
and
. Let
on
, then
on
and
(228)Remark 2.3.
We now define
(229)A simple calculation shows that
(230)Then, we have the following results.
(i)Suppose that
. Taking
, there exists
(
can be chosen small arbitrarily) such that
(231)Hence,
(232)It follows from Remark 2.2 that the hypothesis (2.2) of Theorem 2.1 is satisfied if
.
(ii)Suppose that
. Taking
, there exists
(
can be chosen large arbitrarily) such that
(233)Hence,
(234)which satisfies the hypothesis (2.1) of Theorem 2.1.
(iii)Suppose that
. Taking
, there exists
(
can be chosen small arbitrarily) such that
(235)Hence,
(236)which satisfies the hypothesis (2.1) of Theorem 2.1.
(iv)Suppose that
. Taking
, there exists a
(
can be chosen large arbitrarily) such that
(237)Hence, we have the following two cases.
Case i.
Assume that
is bounded, say
(238)for some constant
. Taking
(since
can be chosen large arbitrarily,
can be chosen large arbitrarily, too),
(239)Case ii.
Assume that
is unbounded, then there exist a
(
can be chosen large arbitrarily) and
such that
(240)It follows from
and (2.37) that
(241)By Cases (i), (ii) and Remark 2.2, we see that the hypothesis (2.2) of Theorem 2.1
is satisfied if
.
We immediately conclude the following corollaries.
Corollary 2.4.
(BVPλ) has at least one positive solution for
if one of the following conditions holds:




Proof.
It follows from Remark 2.3 and Theorem 2.1 that the desired result holds, immediately.
Corollary 2.5.
Let



on
for some
and
.
Then, for
, (BVPλ) has at least two positive solutions
and
such that
(242)Proof.
It follows from Remark 2.3 that there exist two real numbers
satisfying
(243)Hence, by Theorem 2.1 and Remark 2.2, we see that for each
, there exist two positive solutions
and
of (BVPλ) such that
(244)Thus, we complete the proof.
Corollary 2.6.
Let



on
, for some
.
Then, for
, (BVPλ) has at least two positive solutions
and
such that
(245)Proof.
It follows from Remark 2.3 that there exist two real numbers
satisfying
(246)Hence, by Theorem 2.1 and Remark 2.2, we see that, for each
, (BVPλ) has two positive solutions
and
such that
(247)Thus, we completed the proof.
3. Examples
To illustrate the usage of our results, we present the following examples.
Example 3.1.
Consider the following boundary value problem:
(BVP1)Clearly,
(31)If we take
, then it follows from
of Corollary 2.4 that (BVP.1) has a solution if
.
Example 3.2.
Consider the following boundary value problem:
(BVP2)Clearly,
(32)If we take
, then it follows from
of Corollary 2.4 that (BVP.2) has a solution if
.
Example 3.3.
Consider the following boundary value problem:
(BVP3)Clearly, if we take
and
,
(33)Hence, it follows from Corollary 2.5 that (BVP.3) has two solutions if
.
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