Abstract
In this paper, we consider the nonlinear viscoelastic equation
, in a bounded domain with initial conditions and Dirichlet boundary conditions. We
prove an arbitrary decay result for a class of kernel function g without setting the function g itself to be of exponential (polynomial) type, which is a necessary condition for
the exponential (polynomial) decay of the solution energy for the viscoelastic problem.
The key ingredient in the proof is based on the idea of Pata (Q Appl Math 64:499-513,
2006) and the work of Tatar (J Math Phys 52:013502, 2010), with necessary modification
imposed by our problem.
Mathematical Subject Classification (2010): 35B35, 35B40, 35B60
Keywords:
Viscoelastic equation; Kernel function; Exponential decay; Polynomial decay1 Introduction
It is well known that viscoelastic materials have memory effects. These properties are due to the mechanical response influenced by the history of the materials themselves. As these materials have a wide application in the natural sciences, their dynamics are of great importance and interest. From the mathematical point of view, their memory effects are modeled by an integro-differential equations. Hence, questions related to the behavior of the solutions for the PDE system have attracted considerable attention in recent years. Many authors have focused on this problem for the last two decades and several results concerning existence, decay and blow-up have been obtained, see [1-28] and the reference therein.
In [3], Cavalcanti et al. studied the following problem
where Ω ⊂ RN, N ≥ 1, is a bounded domain with a smooth boundary ∂Ω, γ ≥ 0,
if N ≥ 3 or ρ > 0 if N = 1, 2, and the function g: R+ → R+ is a nonincreasing function. This type of equations usually arise in the theory of
viscoelasticity when the material density varies according to the velocity. In that
paper, they proved a global existence result of weak solutions for γ ≥ 0 and a uniform decay result for γ > 0. Precisely, they showed that the solutions goes to zero in an exponential rate
for γ > 0 and g is a positive bounded C1-function satisfying
and
for all t ≥ 0 and some positive constants ξ1 and ξ2. Later, this result was extended by Messaoudi and Tatar [15] to a situation where a nonlinear source term is competing with the dissipation terms induced by both the viscoelasticity and the viscosity. Recently Messaoudi and Tatar [14] studied problem (1.1) for the case of γ = 0, they improved the result in [3] by showing that the solution goes to zero with an exponential or polynomial rate, depending on the decay rate of the relaxation function g.
The assumptions (1.2) and (1.3), on g, are frequently encountered in the linear case (ρ = 0), see [1,2,4-6,13,22,23,29-31]. Lately, these conditions have been weakened by some researchers. For instance, instead of (1.3) Furati and Tatar [8] required the functions eαt g(t) and eαtg'(t) to have sufficiently small L1-norm on (0, ∞) for some α > 0 and they can also have an exponential decay of solutions. In particular, they do not impose a rate of decreasingness for g. Later on Messaoudi and Tatar [21] improved this result further by removing the condition on g'. They established an exponential decay under the conditions g'(t) ≤ 0 and eαt g(t) ∈ L1(0, ∞) for some large α > 0. This last condition was shown to be necessary condition for exponential decay [7]. More recently Tatar [25] investigated the asymptotic behavior to problem (1.1) with ρ = γ = 0 when h(t)g(t) ∈ L1(0, ∞) for some nonnegative function h(t). He generalized earlier works to an arbitrary decay not necessary of exponential or polynomial rate.
Motivated by previous works [21,25], in this paper, we consider the initial boundary value problem for the following nonlinear viscoelastic equation:
with initial conditions
and boundary condition
where Ω ⊂ RN, N ≥ 1, is a bounded domain with a smooth boundary ∂Ω. Here ρ, p > 0 and g represents the kernel of the memory term, with conditions to be stated later [see assumption (A1)-(A3)].
We intend to study the arbitrary decay result for problem (1.4)-(1.6) under the weaker
assumption on g, which is not necessarily decaying in an exponential or polynomial fashion. Indeed,
our result will be established under the conditions g'(t) ≤ 0 and
for some nonnegative function ξ(t). Therefore, our result allows a larger class of relaxation functions and improves
some earlier results concerning the exponential decay or polynomial decay.
The content of this paper is organized as follows. In Section 2, we give some lemmas and assumptions which will be used later, and we mention the local existence result in Theorem 2.2. In Section 3, we establish the statement and proof of our result related to the arbitrary decay.
2 Preliminary results
In this section, we give some assumptions and lemmas which will be used throughout
this work. We use the standard Lebesgue space Lp(Ω) and Sobolev space
with their usual inner products and norms.
Lemma 2.1. (Sobolev-Poincaré inequality) Let
, the inequality
holds with the optimal positive constant cs, where || · ||p denotes the norm of Lp(Ω).
Assume that ρ satisfies
With regards to the relaxation function g(t), we assume that it verifies
(A1) g(t) ≥ 0, for all t ≥ 0, is a continuous function satisfying
(A2) g'(t) ≤ 0 for almost all t > 0.
(A3) There exists a positive nondecreasing function ξ(t): [0, ∞) → (0, ∞) such that
is a decreasing function and
Now, we state, without a proof, the existence result of the problem (1.4)-(1.6) which can be established by Faedo-Galerkin methods, we refer the reader to [3,5].
Theorem 2.2. Suppose that (2.1) and (A1) hold, and that
. Assume
, if N ≥ 3, p > 0, if N = 1, 2. Then there exists at least one global solution u of (1.4)-(1.6) satisfying
Next, we introduce the modified energy functional for problem (1.4)-(1.6)
where
Lemma 2.3. Let u be the solution of (1.4)-(1.6), then the modified energy E(t) satisfies
Proof. Multiplying Eq. (1.4) by ut and integrating it over Ω, then using integration by parts and the assumption (A1)-(A2), we obtain (2.6).
Remark. It follows from Lemma 2.3 that the energy is uniformly bounded by E(0) and decreasing in t. Besides, from the definition of E(t) and (2, 2), we note that
3 Decay of the solution energy
In this section, we shall state and prove our main result. For this purpose, we first define the functional
where λi are positive constants, i = 1, 2, 3 to be specified later and
here
Remark. This functional was first introduced by Tatar [25] for the case of ρ = 0 and without imposing the dispersion term and forcing term as far as (1.4) is concerned.
The following Lemma tells us that L(t) and E(t) + Φ3(t) are equivalent.
Lemma 3.1. There exists two positive constants β1 and β2 such that the relation
holds for all t ≥ 0 and λi small, i = 1, 2.
Proof. By Hölder inequality Young's inequality Lemma 2.1, (2.7) and (2.2), we deduce that
and
where
. Therefore, from above estimates, the definition of E(t) by (2.4) and (2.2), we have
and
where
,
, and
. Hence, selecting λi , i = 1, 2 such that
and again from the definition of E(t), there exist two positive constants β1 and β2 such that
To obtain a better estimate for
, we need the following Lemma which repeats Lemma 2 in [25].
Lemma 3.2. For t ≥ 0, we have
Proof. Straightforward computations yield this identity.
Now, we are ready to state and prove our result. First, we introduce the following
notations as in [24,25]. For every measurable set A ⊂ R+, we define the probability measure
by
The flatness set and the flatness rate of g are defined by
and
Before proceeding, we note that there exists t0 > 0 such that
since g is nonnegative and continuous.
Theorem 3.3. Let
be given. Suppose that (A1)-(A3), (2, 1) and the hypothesis on p hold. Assume further that
,
and
with
Then the solution energy of (1.4)-(1.6) satisfies
where μ and K are positive constants.
Proof. In order to obtain the decay result of E(t), it suffices to prove that of L(t). To this end, we need to estimate the derivative of L(t). It follows from (3.2) and Eq. (1.4) that
which together with the identity (3.6) and (2.2) gives
Next, we would like to estimate
. Taking a derivative of Φ2 in (3.3) and using Eq. (1.4) to get
We now estimate the first two terms on the right-hand side of (3.11) as in [25].
Indeed, for all measure set A and F such that A = R+ - F, we have
To simplify notations, we denote
Using Hölder inequality Young's inequality and (2.2), we see that, for δ1 > 0,
and
Thus, from the definition of
by (3.8), (3.12) becomes
The second term on the right-hand side of (3.11) can be estimated as follows (see [25]), for δ2 > 0,
Using Hölder inequality Young's inequality and (A2) to deal with the fifth term, for δ3 > 0,
Exploiting Hölder inequality Young's inequality Lemma 2.1 and (A2) to estimate the sixth term, for δ4 > 0,
For the last term, thanks to Hölder inequality Young's inequality Lemma 2.1, (2.7), (2.2) and (3.8), we have, for δ5 > 0,
where
. Thus, gathering these estimates (3.13)-(3.17) and using (3.9), we obtain, for t ≥ t0,
Further, taking a derivative of Φ3(t), using the fact that
is a decreasing function and the definition of Φ3(t) by (3.4), we derive that (see [25])
Hence, we conclude from (2.6), (3.10), (3.18) and (3.19) that for any t ≥ t0 > 0,
For
, we consider the sets (see [24,25])
and observe that
where Fg is given in (3.7) and Ng is the null set where g' is not defined. In addition, denoting Fn = R+ - An, then
because An are increasingly nested. Thus, choosing A = An, F = Fn and λ1 = (g* - ε) λ2 for some ε > 0 in (3.20), we obtain
At this point, we take
and select λ2 so that
then (3.21) becomes
For ε, δ2 small enough and large value of n and t0, we see that if
then
and
where
and
Note that α > 0 and 0 < δ < 1 due to
. Furthermore, we require λ2 and λ3 satisfying
and
this is possible because of
. Then, letting δ1 be small enough and using (3.22), we see that
Hence, from the definition of E(t) by (2.4), we have, for all t ≥ t0,
for some positive constant c4. As η(t) is decreasing, we have η(t) ≤ c4 after some t* ≥ t0. Hence, with the help of the right hand side inequality in (3.5), we find
for some positive constant c5 > 0. An integration of (3.23) over (t*, t) gives
Then using the left hand side inequality in (3.5) leads to
Therefore, by virtue of the continuity and boundedness of E(t) and ξ(t) on the interval [0, t*], we infer that
for some positive constants K and μ.
Similar to those remarks as in [25], we have the following remark.
Remark. Note that there is a wide class of relaxation functions satisfying (A3). More precisely,
if ξ(t) = eαt, α > 0, then η(t) = α, this gives the exponential decay estimate
, for some positive constants c1 and c2. Similarly, if ξ(t) = (1 + t)α , α > 0, then we obtain the polynomial decay estimate E (t) ≤ c3 (1 + t)-μ, for some positive constants c3 and μ.
Competing interests
The author declares that they have no competing interests.
Acknowledgements
The authors would like to thank very much the anonymous referees for their valuable comments on this work.
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