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Study on integro-differential equation with generalized p-Laplacian operator

Abstract

We tackle the existence and uniqueness of the solution for a kind of integro-differential equations involving the generalized p-Laplacian operator with mixed boundary conditions. This is achieved by using some results on the ranges for maximal monotone operators and pseudo-monotone operators. The method used in this paper extends and complements some previous work.

MSC: 47H05, 47H09.

1 Introduction

Nonlinear boundary value problems (BVPs) involving the p-Laplacian operator Δ p arise from a variety of physical phenomena such as non-Newtonian fluids, reaction-diffusion problems, petroleum extraction, flow through porous media, etc. Thus, the study of such problems and their generalizations have attracted numerous attention in recent years. Some of the BVPs studied in the literature include the following:

{ Δ p u + g ( x , u ( x ) ) = f ( x ) , a.e. in  Ω , u n = 0 , a.e. on  Γ
(1.1)

whose existence results in L p (Ω) (for various ranges of p) can be found in [14]; a related BVP

{ Δ p u + g ( x , u ( x ) ) = f ( x ) , a.e. in  Ω , ϑ , | u | p 2 u β x ( u ( x ) ) , a.e. on  Γ
(1.2)

was tackled in [57] and later generalized to one that contains a perturbation term | u | p 2 u [8, 9]

{ Δ p u + | u | p 2 u + g ( x , u ( x ) ) = f ( x ) , a.e. in  Ω , ϑ , | u | p 2 u β x ( u ( x ) ) , a.e. on  Γ .
(1.3)

Motivated by Tolksdorf’s work [10] where the following Dirichlet BVP has been discussed:

{ div [ ( C ( x ) + | u | 2 ) p 2 2 u ] = f ( x ) , a.e. in  K ( 1 , S ) , u = g , a.e. in  Σ ( 1 , S ) ,
(1.4)

several generalizations have been investigated. These include [1114]

(1.5)
(1.6)

and

{ div [ ( C ( x ) + | u | 2 ) p 2 2 u ] + ε | u | q 2 u + g ( x , u ( x ) ) = f ( x ) , a.e. in  Ω , ϑ , ( C ( x ) + | u | 2 ) p 2 2 u β x ( u ( x ) ) , a.e. on  Γ ,
(1.7)

where 0C(x) L p (Ω), ε is a nonnegative constant and ϑ denotes the exterior normal derivative of Γ.

Inspired by all this research, recently we have studied the following nonlinear parabolic equation with mixed boundary conditions [15]:

{ u t div [ ( C ( x , t ) + | u | 2 ) p 2 2 u ] + ε | u | p 2 u = f ( x , t ) , ( x , t ) Ω × ( 0 , T ) , ϑ , ( C ( x , t ) + | u | 2 ) p 2 2 u β ( u ) h ( x , t ) , ( x , t ) Γ × ( 0 , T ) , u ( x , 0 ) = u ( x , T ) , a.e.  x Ω .
(1.8)

We tackle the existence of solutions for (1.8) via the study of existence of solutions for two BVPs: (i) the elliptic equation with Dirichlet boundary conditions

{ div [ ( C ( x ) + | u | 2 ) p 2 2 u ] + ε | u | q 2 u = f ( x ) , a.e. in  Ω , γ u = w , a.e. on  Γ
(1.9)

and (ii) the elliptic equation with Neumann boundary conditions

{ div [ ( C ( x ) + | u | 2 ) p 2 2 u ] + ε | u | q 2 u = f ( x ) , a.e. in  Ω , ϑ , ( C ( x ) + | u | 2 ) p 2 2 u β ( u ) h ( x ) , a.e. in  Γ .
(1.10)

By setting up the relations between the auxiliary equations (1.9) and (1.10) and by employing some results on ranges for maximal monotone operators, we showed that (1.8) has a unique solution in L p (0,T; W 1 , p (Ω)), where 2p<+, 1q<+ if pN, and 1q 2 N p N p if p<N.

In this paper, we shall employ the technique used in (1.8), viz. using the results on ranges for nonlinear operators, to study the existence and uniqueness of the solution to a nonlinear integro-differential equation with the generalized p-Laplacian operator. We note that most of the existing methods in the literature used to investigate such problems are based on the finite element method, hence our technique is new in tackling integro-differential equations. We shall consider the following nonlinear integro-differential problem with mixed boundary conditions:

{ u t div [ ( C ( x , t ) + | u | 2 ) p 2 2 u ] + ε | u | q 2 u + a t Ω u d x = f ( x , t ) , ( x , t ) Ω × ( 0 , T ) , ϑ , ( C ( x , t ) + | u | 2 ) p 2 2 u β x ( u ) , ( x , t ) Γ × ( 0 , T ) , u ( x , 0 ) = u ( x , T ) , x Ω .
(1.11)

Our discussion is based on some results on the ranges for maximal monotone operators and pseudo-monotone operators in [1618]. Some new methods of constructing appropriate mappings to achieve our goal are employed. Moreover, we weaken the restrictions on p and q. The paper is outlined as follows. In Section 2 we shall state the definitions and results needed, and in Section 3 we shall establish the existence and uniqueness of the solution to (1.11).

2 Preliminaries

Let X be a real Banach space with a strictly convex dual space X . We use (,) to denote the generalized duality pairing between X and X . For a subset C of X, we use IntC to denote the interior of C. We also use ‘→’ and ‘w-lim’ to denote strong and weak convergences, respectively.

Let X and Y be Banach spaces. We use XY to denote that X is embedded continuously in Y.

The function Φ is called a proper convex function on X [17] if Φ is defined from X to (,+], Φ is not identically +∞ such that Φ((1λ)x+λy)(1λ)Φ(x)+λΦ(y), whenever x,yX and 0λ1.

The function Φ:X(,+] is said to be lower-semicontinuous on X [17] if lim inf y x Φ(y)Φ(x) for any xX.

Given a proper convex function Φ on X and a point xX, we denote by Φ(x) the set of all x X such that Φ(x)Φ(y)+(xy, x ) for every yX. Such elements x are called subgradients of Φ at x, and Φ(x) is called the subdifferential of Φ at x [17].

A mapping T:D(T)=X X is said to be demi-continuous on X if w- lim n T x n =Tx for any sequence { x n } strongly convergent to x in X. A mapping T:D(T)=X X is said to be hemi-continuous on X if w- lim t 0 T(x+ty)=Tx for any x,yX [17].

With each multi-valued mapping A:X 2 X , we associate the subset A 0 as follows [17]:

A 0 x= { y A x : y = | A x | } ,

where |Ax|:=inf{z:zAx}. If X is strictly convex, then D(A)=D( A 0 ) and A 0 is single-valued, which in this case is called the minimal section of A.

A multi-valued mapping B:X 2 X is said to be monotone [18] if its graph G(B) is a monotone subset of X× X in the sense that ( u 1 u 2 , w 1 w 2 )0 for any [ u i , w i ]G(B), i=1,2. The monotone operator B is said to be maximal monotone if G(B) is not properly contained in any other monotone subsets of X× X .

Definition 2.1 [18]

Let C be a closed convex subset of X, and let A:C 2 X be a multi-valued mapping. Then A is said to be a pseudo-monotone operator provided that

  1. (i)

    for each xC, the image Ax is a nonempty closed and convex subset of X ;

  2. (ii)

    if { x n } is a sequence in C converging weakly to xC and if f n A x n is such that lim sup n ( x n x, f n )0, then to each element yC, there corresponds an f(y)Ax with the property that

    ( x y , f ( y ) ) lim inf n ( x n x, f n );
  3. (iii)

    for each finite-dimensional subspace F of X, the operator A is continuous from CF to X in the weak topology.

Lemma 2.1 [19]

Let Ω be a bounded conical domain in R N . If mp>N, then W m , p (Ω) C B (Ω); if 0<mpN and q= N p N m p , then W m , p (Ω) L q (Ω); if mp=N and p>1, then for 1q<+, W m , p (Ω) L q (Ω).

Lemma 2.2 [18]

If B:X 2 X is an everywhere defined, monotone, and hemi-continuous operator, then B is maximal monotone. If B:X 2 X is a maximal monotone operator such that D(B)=X, then B is pseudo-monotone.

Lemma 2.3 [18]

If X is a Banach space and Φ:X(,+] is a proper convex and lower-semicontinuous function, then Φ is maximal monotone from X to X .

Lemma 2.4 [18]

If B 1 and B 2 are two maximal monotone operators in X such that intD( B 1 )D( B 2 ), then B 1 + B 2 is maximal monotone.

Lemma 2.5 [20]

Let X and its dual X be strictly convex Banach spaces. Suppose S:D(S)X X is a closed linear operator and S is the conjugate operator of S. If (u,Su)0 uD(S) and (v, S v)0 vD( S ), then S is a maximal monotone operator possessing a dense domain.

Lemma 2.6 [18]

Any hemi-continuous mapping T:X X is demi-continuous on IntD(T).

Theorem 2.1 [16]

Let X be a real reflexive Banach space with X being its dual space. Let C be a nonempty closed convex subset of X. Assume that

  1. (i)

    the mapping A:C 2 X is a maximal monotone operator;

  2. (ii)

    the mapping B:C X is pseudo-monotone, bounded, and demi-continuous;

  3. (iii)

    if the subset C is unbounded, then the operator B is A-coercive with respect to the fixed element b X , i.e., there exists an element u 0 CD(A) and a number r>0 such that (u u 0 ,Bu)>(u u 0 ,b) for all uC with u>r.

Then the equation bAu+Bu has a solution.

3 Existence and uniqueness of the solution to (1.11)

We begin by stating some notations and assumptions used in this paper. Throughout, we shall assume that

1<qp<+, 1 p + 1 p =1and 1 q + 1 q =1.

Let V= L p (0,T; W 1 , p (Ω)) and V be the dual space of V. The duality pairing between V and V will be denoted by , V . The norm in V will be denoted by V , which is defined by

u V = ( 0 T u ( t ) W 1 , p ( Ω ) p d t ) 1 p ,u(x,t)V.

Let W= L q (0,T; W 1 , p (Ω)) and W be the dual space of W. The norm in W will be denoted by W , which is defined by

v W = ( 0 T v ( t ) W 1 , p ( Ω ) q d t ) 1 q ,v(x,t)W.

In the integro-differential equation (1.11), Ω is a bounded conical domain of a Euclidean space R N where N1, Γ is the boundary of Ω with Γ C 1 [5], ϑ denotes the exterior normal derivative to Γ. Here, || and , denote the Euclidean norm and the inner-product in R N , respectively. Also, 0C(x,t) L p (0,T; W 1 , p (Ω)), f(x,t) V is a given function, T and a are positive constants, and ε is a nonnegative constant. Moreover, β x is the subdifferential of φ x , where φ x =φ(x,):RR for xΓ, and φ:Γ×RR is a given function.

To tackle (1.11), we need the following assumptions which can be found in [5, 14].

Assumption 1 Green’s formula is available.

Assumption 2 For each xΓ, φ x =φ(x,):RR is a proper, convex, and lower-semicontinuous function and φ x (0)=0.

Assumption 3 0 β x (0) and for each tR, the function xΓ ( I + λ β x ) 1 (t)R is measurable for λ>0.

We shall present a series of lemmas before we prove the main result.

Lemma 3.1 Define the function Φ:VR by

Φ(u)= 0 T Γ φ x ( u | Γ ( x , t ) ) dΓ(x)dt,uV.

Then Φ is a proper, convex, and lower-semicontinuous mapping on V. Therefore, Φ:V V , the subdifferential of Φ, is maximal monotone.

Proof The proof of this lemma is analogous to that of Lemma 3.1 in [1]. We give the outline of the proof as follows.

Note that for each sR, the function xΓ β x 0 (s)R is measurable, where β x 0 (s) denotes the minimal section of β x . Since for all s 1 , s 2 R we have

{ x Γ : φ x ( s 1 ) > s 2 } = n { x Γ : i = 1 n s 1 n β x 0 ( i s 1 n ) > s 2 } ,

it implies that for uV, the function φ x (u | Γ (x,t)) is measurable on Γ. Then from the property of φ x , we know that Φ is proper and convex on V.

To see that Φ is lower-semicontinuous on V, let u n u in V. We may assume that there exists a subsequence of u n , for simplicity, we still denote it by u n , such that u n | Γ (x,t)u | Γ (x,t) for xΓ and t(0,T) a.e. This yields

φ x ( u | Γ ( x , t ) ) lim inf n φ x ( u n | Γ ( x , t ) )

for all xΓ and each t(0,T) a.e. since φ x is lower-semicontinuous for each xΓ. It then follows from Fatou’s lemma that for each t(0,T),

Γ φ x ( u | Γ ( x , t ) ) d Γ ( x ) Γ lim inf n φ x ( u n | Γ ( x , t ) ) d Γ ( x ) lim inf n Γ φ x ( u n | Γ ( x , t ) ) d Γ ( x ) .

So, Φ(u) lim inf n Φ( u n ) whenever u n u in V. This completes the proof. □

Lemma 3.2 Define S:D(S)={uV: u t V ,u(x,0)=u(x,T)} V by

Su= u t +a t Ω udx.

Then S is a linear maximal monotone operator possessing a dense domain in V.

Proof It is obvious that S is closed and linear.

For u(x,t),w(x,t)D(S), integrating by parts gives

Then S w= w t a t Ω wdx, where D( S )={wV: w t V ,w(x,0)=w(x,T)}.

For u(x,t)D(S), we find

0 T Ω u t u ( x , t ) d x d t = Ω | u ( x , T ) | 2 d x Ω | u ( x , 0 ) | 2 d x 0 T Ω u t u ( x , t ) d x d t = 0 T Ω u t u ( x , t ) d x d t ,

which implies that

0 T Ω u t u(x,t)dxdt=0.

Similarly, for u(x,t)D(S),

which implies that

a 0 T Ω u(x,t) ( t Ω u d x ) dxdt=0.

Thus,

u , S u V = 0 T Ω u t u(x,t)dxdt+a 0 T Ω u(x,t) ( t Ω u d x ) dxdt=0.

In the same manner, we have w , S w V =0 for wD( S ). Therefore, noting Lemma 2.5 the result follows. □

In view of Lemmas 2.3 and 2.4, we have the following result.

Lemma 3.3 S+Φ:V V is maximal monotone.

Lemma 3.4 [14]

Define the mapping B p , q : W 1 , p (Ω) ( W 1 , p ( Ω ) ) as follows:

( v ¯ , B p , q u ¯ )= Ω ( C ( x , t ) + | u ¯ | 2 ) p 2 2 u ¯ , v ¯ dx+ε Ω | u ¯ | q 2 u ¯ v ¯ dx, u ¯ , v ¯ W 1 , p (Ω).

Then B p , q is maximal monotone.

Lemma 3.5 [14]

Let X 0 denote the closed subspace of all constant functions in W 1 , p (Ω). Let X be the quotient space W 1 , p ( Ω ) X 0 . For u ¯ W 1 , p (Ω), define the mapping P: W 1 , p (Ω) X 0 by

P u ¯ = 1 meas ( Ω ) Ω u ¯ dx.

Then, there is a constant C>0 such that for every u ¯ W 1 , p (Ω),

u ¯ P u ¯ L p ( Ω ) C u ¯ ( L p ( Ω ) ) N .

Here meas(Ω) denotes the measure of Ω.

Definition 3.1 Define A:V V as follows:

v , A u V = 0 T (v, B p , q u)dt 0 T Ω f(x,t)v(x,t)dxdt,u,vV.

Lemma 3.6 The mapping A:V V is everywhere defined, bounded, monotone, and hemi-continuous. Therefore, Lemma  2.2 implies that it is also pseudo-monotone.

Proof From Lemma 2.1, we know that W 1 , p (Ω) C B (Ω) when p>N, and W 1 , p (Ω) L q (Ω) when p=N. If p<N, then W 1 , p (Ω) L N p N p (Ω) L p (Ω) L q (Ω) since 1<qp<+. Thus, for all w ¯ W 1 , p (Ω), w ¯ L q ( Ω ) k w ¯ W 1 , p ( Ω ) , where k>0 is a constant. Therefore, for u,vV, we have

0 T u L q ( Ω ) q dtconst 0 T u W 1 , p ( Ω ) q dt=const u W q

and

0 T v L q ( Ω ) q dtconst 0 T v W 1 , p ( Ω ) q dt=const v W q .

Moreover, since 1<qp<+, then L p (0,T; W 1 , p (Ω)) L q (0,T; W 1 , p (Ω)), which implies that u W u V and v W v V for u,vV.

If p2, then for u,vV, we have

which implies that A is everywhere defined and bounded.

If 1<p<2, then for u,vV, we have

which also implies that A is everywhere defined and bounded.

Since B p , q is monotone, we can easily see that for u,vV,

u v , A u A v V = 0 T (uv, B p , q u B p , q v)dt0,

which implies that A is monotone.

To show that A is hemi-continuous, it suffices to show that for any u,v,wV and k[0,1], w , A ( u + k v ) A u V 0, as k0. Noting the fact that B p , q is hemi-continuous and using the Lebesgue’s dominated convergence theorem, we have

0 lim k 0 | w , A ( u + k v ) A u V | 0 T lim k 0 | ( w , B p , q ( u + k v ) B p , q u ) |dt=0.

Hence, A is hemi-continuous.

This completes the proof. □

Lemma 3.7 The mapping A:V V satisfies that for uD(S),

u u 0 , A u V u V +,
(3.1)

as u V + in V.

Proof First, we shall show that for uV,

u V +

is equivalent to

u 1 meas ( Ω ) Ω u d x V +.

In fact, from Lemma 3.5, we know that for uV,

u 1 meas ( Ω ) Ω u d x L p ( Ω ) C u ( L p ( Ω ) ) N ,

where C is a positive constant. Thus,

which implies that

u 1 meas ( Ω ) Ω u d x V [ ( C p + 1 ) 0 T u ( L p ( Ω ) ) N p d t ] 1 p ( C p + 1 ) 1 p u V .
(3.2)

On the other hand, we have

u 1 meas ( Ω ) Ω u d x W 1 , p ( Ω ) u W 1 , p ( Ω ) 1 meas ( Ω ) Ω u d x W 1 , p ( Ω ) ,

which implies that

u W 1 , p ( Ω ) u 1 meas ( Ω ) Ω u d x W 1 , p ( Ω ) +const.

Hence,

u V u 1 meas ( Ω ) Ω u d x V +const.
(3.3)

In view of (3.2) and (3.3), we have shown that for uV, u V + is equivalent to u 1 meas ( Ω ) Ω u d x V +.

Next, we shall show that A satisfies (3.1). In fact, we have

(3.4)

If 1<p<2, then

(3.5)

From (3.2) and (3.3), we know that

0 T Ω | u | p dxdt 1 C p + 1 u 1 meas ( Ω ) Ω u d x V p 1 C p + 1 u V p +const.

Also,

0 T Ω C ( x , t ) p 2 dxdt C ( x , t ) V p <+.

It follows from (3.5) that

0 T Ω ( C ( x , t ) + | u | 2 ) p 2 2 u , u d x d t u V +ε 0 T Ω | u | q d x d t u V +,

as u V +.

Moreover, we have

(3.6)

Therefore, it follows from (3.4), (3.5), and (3.6) that A satisfies (3.1) when 1<p<2.

If p2, then

(3.7)

where M is a positive constant. We can easily see that

u 1 | Ω | Ω u d x V p u 0 V u 1 | Ω | Ω u d x V p p u V +,

as u V +. Moreover, if 0 T Ω | u | q dxdt<+, then

ε ( 0 T Ω | u | q d x d t ) 1 q [ ( 0 T Ω | u | q d x d t ) 1 1 q u 0 V ] u V 0,

as u V +; while if 0 T Ω | u | q dxdt+,

ε ( 0 T Ω | u | q d x d t ) 1 q [ ( 0 T Ω | u | q d x d t ) 1 1 q u 0 V ] u V >0.

Hence, the right side of (3.7) tends to +∞ as u V +, which implies that A satisfies (3.1).

This completes the proof. □

Lemma 3.8 If w(x,t)Φ(u), then w(x,t)= w ˜ (x,t) β x (u) a.e. on Γ×(0,T).

Proof If w(x,t)Φ(u), then from the definition of subdifferential, we have

0 T Γ φ x ( u | Γ ( x , t ) ) d Γ ( x ) d t 0 T Γ φ x ( w | Γ ( x , t ) ) d Γ ( x ) d t + 0 T Γ w ( x , t ) ( u w ) d Γ ( x ) d t ,

which implies that the result is true. □

We are now ready to prove the main result.

Theorem 3.1 The integro-differential equation (1.11) has a unique solution in V for f(x,t) V .

Proof First, we shall show the existence of a solution. Noting Lemmas 2.6, 3.6, 3.7 and 3.3, and by using Theorem 2.1, we know that there exists u(x,t)D(S)V such that

0=Su+Au+Φ(u).
(3.8)

Then we have for all wV,

u w , S u V + u w , A u V + u w , Φ ( u ) V =0.

The definition of subdifferential implies that

u w , u t V + u w , a t Ω u d x V + u w , A u V +Φ(u)Φ(w)0.

From the definition of S, we have

u(x,0)=u(x,T).
(3.9)

Moreover,

(3.10)

Let w=u±ψ, where ψ C 0 (Ω×(0,T)). Then we have

From the properties of a generalized function, we get

(3.11)

Noting (3.10) again, by using Green’s formula, we have

Then using (3.10), we obtain

Φ(w)Φ(u) 0 T Γ ϑ , ( C ( x , t ) + | u | 2 ) p 2 2 u (wu) | Γ dΓ(x)dt.

Thus, ϑ, ( C ( x , t ) + | u | 2 ) p 2 2 uΦ(u).

In view of Lemma 3.8, we have ϑ, ( C ( x , t ) + | u | 2 ) p 2 2 u β x (u) a.e. on Γ×(0,T). Combining it with (3.8) and (3.11), we know that (1.11) has a solution in V.

Next, we shall prove the uniqueness of the solution. Let u(x,t) and v(x,t) be two solutions of (1.11). By (3.8), we have

u v , ( A + Φ ) u ( A + Φ ) v V = u v , S u S v V 0

since S is monotone. But A+Φ is monotone too, so u v , S u S v V =0, which implies that u(x,t)=v(x,t).

The proof is complete. □

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Acknowledgements

Li Wei is supported by the National Natural Science Foundation of China (No. 11071053), the Natural Science Foundation of Hebei Province (No. A2010001482) and the Project of Science and Research of Hebei Education Department (the second round in 2010).

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Correspondence to Ravi P Agarwal.

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Wei, L., Agarwal, R.P. & Wong, P.J. Study on integro-differential equation with generalized p-Laplacian operator. Bound Value Probl 2012, 131 (2012). https://doi.org/10.1186/1687-2770-2012-131

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