Abstract
The unique continuation theorems for elliptic differential-operator equations with variable coefficients in vector-valued Lp-space are investigated. The operator-valued multiplier theorems, maximal regularity properties and the Carleman estimates for the equations are employed to obtain these results. In applications the unique continuation theorems for quasielliptic partial differential equations and finite or infinite systems of elliptic equations are studied.
AMS: 34G10; 35B45; 35B60.
Keywords:
Carleman estimates; unique continuation; embedding theorems; Banach-valued function spaces; differential operator equations; maximal Lp-regularity; operator-valued Fourier multipliers; interpolation of Banach spaces1 Introduction
The aim of this article, is to present a unique continuation result for solutions of a differential inequalities of the form:
where
here aij are real numbers, A = A (x), Ak = Ak (x) and V (x) are the possible linear operators in a Banach space E.
Jerison and Kenig started the theory of Lp Carleman estimates for Laplace operator with potential and proved unique continuation results for elliptic constant coefficient operators in [1]. This result shows that the condition V ∈ Ln/2,loc is in the best possible nature. The uniform Sobolev inequalities and unique continuation results for second-order elliptic equations with constant coefficients studied in [2]. This was latter generalized to elliptic variable coefficient operators by Sogge in [3]. There were further improvement by Wolff [4] for elliptic operators with less regular coefficients and by Koch and Tataru [5] who considered the problem with gradients terms. A comprehensive introductions and historical references to Carleman estimates and unique continuation properties may be found, e.g., in [5]. Moreover, boundary value problems for differential-operator equations (DOEs) have been studied extensively by many researchers (see [6-18] and the references therein).
In this article, the unique continuation theorems for elliptic equations with variable
operator coefficients in E-valued Lp spaces are studied. We will prove that if 
,
, V ∈ Lμ (Rn; L(E)), p, μ∈ (1, ∞) and
satisfies (1), then u is identically zero if it vanishes in a nonempty open subset, where
is an E-valued Sobolev-Lions type space. We prove the Carleman estimates to obtain unique
continuation. Specifically, we shall see that it suffices to show that if
, then
In the Hilbert space L2 (Rn; H), we derive the following Carleman estimate
Any of these inequalities would follow from showing that the adjoint operator Lt (x; D) = etwL (x; D) e-tw satisfies the following relevant local Sobolev inequalities
uniformly to t, where L0t = etwL0e-tw. In application, putting concrete Banach spaces instead of E and concrete operators instead of A, we obtain different results concerning to Carleman estimates and unique continuation.
2 Notations, definitions, and background
Let R and C denote the sets of real and complex numbers, respectively. Let
Let E and E1 be two Banach spaces, and L (E, E1) denotes the spaces of all bounded linear operators from E to E1. For E1 = E we denote L (E, E1) by L (E). A linear operator A is said to be a φ-positive in a Banach space E with bound M > 0 if D (A) is dense on E and
with λ ∈ Sφ, φ ∈ (0, π], I is identity operator in E. We will sometimes use A + ξ or Aξ instead of A + ξI for a scalar ξ and (A + ξI)-1 denotes the inverse of the operator A + ξI or the resolvent of operator A. It is known [19, §1.15.1] that there exist fractional powers Aθ of a positive operator A and
We denote by Lp (Ω; E) the space of all strongly measurable E-valued functions on Ω with the norm
By Lp,q (Ω) and
let us denoted, respectively, the (p, q)-integrable function space and Sobolev space with mixed norms, where 1 ≤ p, q < ∞, see [20].
Let E0 and E be two Banach spaces and E0 is continuously and densely embedded E.
Let l be a positive integer.
We introduce an E-valued function space
(sometimes we called it Sobolev-Lions type space) that consist of all functions u ∈ Lp (Ω; E0) such that the generalized derivatives
are endowed with the
The Banach space E is called an UMD-space if the Hilbert operator
dy is bounded in Lp (R, E), p ∈ (1, ∞) (see e.g., [21,22]). UMD spaces include, e.g., Lp, lp spaces and Lorentz spaces Lpq, p, q ∈ (1, ∞).
Let E1 and E2 be two Banach spaces. Let S (Rn; E) denotes a Schwartz class, i.e., the space of all E-valued rapidly decreasing smooth functions on Rn. Let F and F-1denote Fourier and inverse Fourier transformations, respectively. A function Ψ ∈ Cm (Rn; L (E1, E2)) is called a multiplier from Lp (Rn; E1) to Lq (Rn; E2) for p, q ∈ (1, ∞) if the map u → Ku = F-1 Ψ (ξ) Fu, u ∈ S (Rn; E1) is well defined and extends to a bounded linear operator
We denote the set of all multipliers from Lp (Rn; E1) to Lq (Rn; E2) by
. For E1 = E2 = E and q = p we denote
by Mp (E). The Lp-multipliers of the Fourier transformation, and some related references, can be found
in [19, § 2.2.1-§ 2.2.4]. On the other hand, Fourier multipliers in vector-valued
function spaces, have been studied, e.g., in [23-28].
A set K ⊂ L (E1, E2) is called R-bounded [22,23] if there is a constant C such that for all T1, T2, . . . , Tm ∈ K and u1,u2, . . . , um ∈ E1, m ∈ N
where {rj} is a sequence of independent symmetric {-1, 1}-valued random variables on [0,1]. The smallest C for which the above estimate holds is called a R-bound of the collection K and denoted by R (K).
Let
For any r = (r1, r2, . . . , rn), ri ∈ [0, ∞) the function (iξ)r, ξ ∈ Rn will be defined such that
where
Definition 2.1. The Banach space E is said to be a space satisfying a multiplier condition with respect to p, q ∈ (1, ∞) (with respect to p if q = p) when for Ψ ∈ C(n) (Rn; L (E1, E2)) if the set
Definition 2.2. The φ-positive operator A is said to be a R-positive in a Banach space E if there exists φ ∈ [0, π) such that the set
is R-bounded.
Remark 2.1. By virtue of [29] or [30] UMD spaces satisfy the multiplier condition with respect to p ∈ (1, ∞).
Note that, in Hilbert spaces every norm bounded set is R-bounded. Therefore, in Hilbert spaces all positive operators are R-positive. If A is a generator of a contraction semigroup on Lq, 1 ≤ q ≤ ∞ [31], A has the bounded imaginary powers with
,
or if A is a generator of a semigroup with Gaussian bound in E ∈ UMD then those operators are R-positive (see e.g., [24]).
It is well known (see e.g., [32]) that any Hilbert space satisfies the multiplier condition with respect to p ∈ (1, ∞). By virtue of [33] Mikhlin conditions are not sufficient for operator-valued multiplier theorem. There are however, Banach spaces which are not Hilbert spaces but satisfy the multiplier condition (see Remark 2.1).
Let
,
be a collection of multipliers in
. We say that Hk is a uniform collection of multipliers if there exists a constant M > 0, independent on h ∈ K, such that
for all h ∈ K and u ∈ S (Rn; E1).
We set
In view of [17, Theorem A0], we have
Theorem 2.0. Let E1 and E2 be two UMD spaces and let
If
uniformly with respect to h ∈ K then Ψh (ξ) is a uniformly collection of multipliers from Lp (Rn; E1) to Lq (Rn; E2).
Let
Embedding theorems in Sobolev-Lions type spaces were studied in [13-18,32,34]. In a similar way as [17, Theorem 3] we have
Theorem 2.1. Suppose the following conditions hold:
(1) E is a Banach space satisfying the multiplier condition with respect to p, q ∈ (1, ∞) and A is a R-positive operator on E;
(2) l is a positive and αk are nonnegative integer numbers such that 0 ≤ μ ≤ 1 - ϰ, t and h are positive parameters.
Then the embedding
is continuous and there exists a positive constant Cµ such that for
the uniform estimate holds
Moreover, for
the following uniform estimate holds
3 Carleman estimates for DOE
Consider at first the equation with constant coefficients
where
and A is the possible unbounded operator in a Banach space E.
Let
and t is a positive parameter.
Remark 3.1. It is clear to see that
where
. Let L0t (x, ξ) is the principal operator symbol of L0t (x, D) on the domain B0, i.e.,
where
Our main aim is to show the following result:
Remark 3.2. Since Q(ξ) ∈ S (φ) for all φ ∈ [0, π) due to positivity of A, the operator function A + |ξ||2, ξ ∈ Rn is uniformly positive in E. So there are fractional powers of A+|ξ||2 and the operator function
is positive in E (see e.g., [19, §1. 15.1]).
First, we will prove the following result.
Theorem 3.1. Suppose A is a positive operator in a Hilbert space H. Then the following uniform Sobolev type estimate holds for the solution of Equation (3)
By virtue of Remark 3.1 it suffices to prove the following uniform coercive estimate
To prove the Theorem 3.1, we shall show that L0t (x, D) has a right parametrix T, with the following properties.
Lemma 3.1. For t > 0 there are functions K = Kt and R = Rt so that
where δ denotes the Dirac distribution. Moreover, if we let T = Tt be the operator with kernel K, i.e.,
and R is the operator with kernel R (x, y), then for large t > 0, the adjoint of these operators satisfy the following estimates
Proof. By Remark 3.2 the operator function
is positive in E for all ξ ∈ Rn. Since tw1 + iξ1 ∈ S(φ), due to positivity of A, for
the factor
has a bounded inverse
for all ξ ∈ Rn, t > 0 and
Therefore, we call Gt (x, ξ) the regular factor. Consider now the second factor
By virtue of operator calculus and fractional powers of positive operators (see e.g., [19, §1.15.1] or [35]) we get that - [tw1 + iξ1] ∉ S (φ) for ξ1 = 0 and tw1 = |ξ||, i.e., the operator Bt (x, ξ) does not has an inverse, in the following set
So we will called Bt the singular factor and the set Δt call singular set for the operator function Bt. The operator
cannot be bounded in the set Δt. Nevertheless, the operator
, and hence
, can be bounded when (x, ξ) is sufficiently far from Δt. For instance, if we define
by properties of positive operators we will get the same estimate of type (10) for the singular factor Bt. Hence, using this fact and the resolvent properties of positive operators we obtain the following estimate
where the constant C is independent of x, ξ, t and cΓt denotes the complement of Γt.
Let
such that, β(ξ) = 0 if
and β (ξ) = 0 near the origin. We then define
and notice that β0 (ξ) = 0 on Γt. Hence, if we define
and recall (11), then by [31] it follows from standard microlocal arguments that
where R0t belongs to a bounded subset of S-1 which is independent of t. Since operator
also has the same property, it follows that for all 
By reasoning as in [31] we get that tR0t belongs to a bounded subset of S0. So, we have the following estimate
Moreover, the Remark 3.2, positivity properties of A and, (11) and (12) imply that, the operator functions
and
are uniformly bounded. Then, if we let T0 be the operator with kernel K0 (x, y), by using the Minkowski integral inequality and Plancherel's theorem we obtain
For inverting L0t (x, D) on the set Γt we will require the use of Fourier integrals with complex phase. Let β1 (ξ) = 1 - β0 (ξ). We will construct a Fourier integral operator T1 with kernel
so that the analogs of (16) and the estimates (7)-(9) are satisfied. Since
is uniformly bounded on Γt, we should expect to construct the phase function Φ in (13) using the factor Bt (x, ξ). Specifically, we would like Φ to satisfy the following equation
The Equation (14) leads to complex eikonal equation (i.e., a non-linear partial differential equation with complex coefficients).
Since w1 (x) = 1 + x1, w1 (y) = 1 + y1, we have
is a solution of (15). To use this we get
Next, if we set
then it follows from L0t (x, ξ) = Gt (x, ξ)Bt (x, ξ) and (14) that
Consequently, (16)-(18) imply that
By reasoning as in [3] we obtain that the first and second summands in (19) belong to a bounded subset of S0. So, we see that the equality (5) must hold. Now we let K (x, y) = K0 (x, y) + K1 (x, y) and R (x, y) = R0 (x, y) + R1 (x, y), where
Due to regularity of kernels, by using of Minkowski and Hölder inequalities we get the analog estimate as (7) and (9) for the operators T0 and R10. Thus, in order to finish the proof, it suffices to show that for f ∈L2 (B0; E) one has
However, since R1,1 ≈ tT1, we need only to show the following
By using the Minkowski inequalities we get
where
. The estimates (13) and (16) imply that
where
Consequently, it follows from Plancherel's theorem that
Note that for every N we have
Since A is a positive operator in E, we have
when
. Then by using the above estimate it not easy to check that
i.e.,
Moreover, it is clear that
Thus from (24) by using the above relations and Young's inequality we obtain the desired estimate
Moreover, by using the estimate (10) and the resolvent properties of the positive operator A we have
The last two estimates then, imply the estimates (20)-(22).
Proof of Theorem 3.1: The estimates (7)-(9) imply the estimate (5), i.e., we obtain the assertion of the Theorem 3.1.
4 Lp-Carleman estimates and unique continuation for equation with variable coefficients
Consider the following DOE
where
and A is the possible unbounded operator in a Banach space E and aij are
real-valued smooth functions in Bε = {x ∈ Rn, |x| < ε}.
Condition 4.1. There is a positive constant γ such that
for all ξ ∈ Rn, x ∈ 
The main result of the section is the following
Theorem 4.1. Let E be a Banach space satisfies the multiplier condition and A be a R-positive operator in E. Suppose the Condition 4.1 holds, n ≥ 3, p =
and p' is the conjugate of p, w =
and aij ∈ C∞ (Bε). Then for
( Bε; E(A)) and
the following estimates are satisfied:
Proof. As in the proof of Theorem 3.1, it is sufficient to prove the following estimates
where,
Consequently, since w1 ≃ 1 on Bε, it follows that, if we let Qt (εx, D) be the differential operator whose adjoint equals
then it suffices to prove the following
The desired estimates will follow if we could constrict a right operator-valued parametrix T, for Qt* (εx, D) satisfying Lp estimates. these are contained in the following lemma.
Lemma 4.1. For t > 0 there are functions K = Kt and R = Rt, so that
where δ denotes the Dirac distribution. Moreover, if we let T = Tt be the operator with kernel K (x, y) and R be the operator with kernel R (x, y), then if ε and
are sufficiently small, the adjoint of these operators satisfy the following uniform
estimates
Proof. The key step in the proof is to find a factorization of the operator-valued symbol
that will allow to microlocally invert
near the set where
vanishes. Note that, after making a suitable choice of coordinates, it is enough
to show that if L (x, D) is of the form
therefore, we can expressed
as
where
where
The ellipticity of Q(x, D) and the positivity of the operator A, implies that the factor Gt (x, ξ) never vanishes and as in the proof of Theorem 3.1 we get that
i.e., the operator function Gt (εx, ξ) has uniformly bounded inverse for (x, ξ) ∈ Bε ×Rn. One can only investigate the factor Bt (εx, ξ). In fact, if we let
then the operator function Bt (x, ξ) is not invertible for (x, ξ) ∈ Δt. Nonetheless, Bt (εx, ξ) and
can be have a bounded inverse when (x, ξ) is sufficiently far away. For instance, if we define
by properties of positive operators we will get the same estimate of type (37) for the singular factor Bt. Hence, we using this fact and the resolvent properties of positive operators we obtain the following estimate
As in § 3, we can use (38) to microlocallity invert
away from Γt
. To do this, we first fix
as in § 3. We then define
It is clear that β0 (ξ) = 0 on Γt. Consequently, if we define
and recall (37), then we can conclude that standard microlocal arguments give that
where R0 belongs to a bounded subset of S-1 that independent of t. Since the adjoint operator
also is abstract pseudodifferential operator with this property, by reasoning as
in [31, Theorem 6] it follows that
Moreover, the positivity properties of A and the estimate (38) imply that the operator functions
are uniformly bounded. Next, let T0 be the operator with kernel K0. Then in a similar way as in [31] we obtain that
which also the first estimate is stronger than the corresponding inequality in Lemma
4.1. Finally, since T0 ∈ S-2 and
it follows from imbedding theorem in abstract Sobolev spaces [17] that
Thus, we have shown that the microlocal inverse corresponding to cΓt, satisfies the desired estimates.
Let β1 (ξ) = 1-β0 (ξ). To invert
for (x, ξ) ∈ Γt, we have to construct a Fourier integral operator T1, with kernel
such that the analogs of (39) and (32)-(35) are satisfied. For this step the factorization
(36) of the symbol
will be used. Since the factor Gt (εx, ξ) has a bounded inverse for (x, ξ) ∈ Γt, the previous discussions show that we should try to construct the phase function
in (46) using the factor Bt (εx, ξ). We would like Φ (x, y, ξ) to solve the complex eikonal equation
Since Bt (εx, Φx) - Bt (εy, ξ) is a scalar function (it does not depend of operator A ), by reasoning as in [3, Lemma 3.4] we get that
where ϕ is real and defined as
while
and
Then we obtain from the above that
Next, if we set
then it follows from (36) and (48) that
for every N when β1 (ξ) ≠ 0. Consequently, (49), (50) imply that
By reasoning as in Theorem 3.1 we obtain from (51) that
where
while R10 belongs to a bounded subset of S-1 and tR10 belongs to a bounded subset of S0. In view of this formula, we see that if we let K (x, y) = K0 (x, y) + K1 (x, y) and R (x, y) = R0 (x, y)+R1 (x, y), where R1 = R10 +R11, then we obtain (31). Moreover, since R10 satisfies the desired estimates, we see from Minkowski inequality that, in order to
finish the proof of Lemma 4.1, it suffices to show that for 
To prove the above estimates we need the following prepositions for oscillatory integral in E-valued Lp spaces which generalize the Carleson and Sjolin result [36].
Preposition 4.1. Let E be Banach spaces and
. Moreover, suppose Φ ∈ C∞ satisfies | ∇Φ| ≥ γ > 0 on supp A. Then for all λ > 1 the following holds
where CN-depends only on γ if Φ and A (x) belong to a bounded subset of C∞ and C∞ (Rn, L (E)) and A is supported in a fixed compact set.
Proof. Given x0 ∈ supp A. There is a direction ν ∈ Sn-1 such that |(ν, ∇Φ)| ≥
on some ball centered at x0. Thus, by compactness, we can choose a partition of unity
consisting of a finite number of terms and corresponding unit vectors νj such that
on supp A and
on supp φj. For Aj = φjA it suffices to prove that for each j
After possible changing coordinates we may assume that νj = (1, 0, . . . , 0) which means that
on supp φj. If let
, then
. Consequently, if
is a adjoint, then
Since our assumption imply that (L*)N Aj (x) = O (λ-N), the result follows.
Preposition 4.2. Suppose Φ ∈ C∞ is a phase function satisfying the non-degeneracy condition det
on the support of
Then for
the following estimates hold
Proof. In view of [3, Remark 2.1] we have
where |y - z| is small. By using a smooth partition of unity we can decompose A (x, y) into a finite number of pieces each of which has the property that (57) holds on its support. So, by (57) we can assume
on supp A for same C > 0. To use this we notice that
where
Hence, by virtue of Preposition 4.1 and by (58) we obtain that
Consequently, by Young's inequality, the operator with kernel Kλ acts
By (59) we get that
Moreover, it is clear to see that
Therefore, by applying Riesz interpolation theorem for vector-valued Lp spaces (see e.g., [19, § 1.18]) we get the assertion.
In a similar way as in [3, Preposition 3.6] we have.
Preposition 4.3. The kernel K1 (x, y) can be written as
where, for every fixed N, the operator functions Aj satisfy
and moreover, the phase functions φj are real and the property that when ε is small enough, 0 < δ ≤ ε and y1 ∈ [-ε, ε] is fixed, the dilated functions
in the some fixed neighborhood of the function
in the C∞ topology. Then, the following estimates holds
Proof. By representation of K1 (x, y) and Φ (x, y, ξ) we have
Then, by using (36) in view of positivity of operator A, by reasoning as in [3, Preposition 3.6] we obtain the assertion.
Let us now show the end of proof of Lemma 4.1. Let
be supported in
such that
and set
. Then we define kernels K1,ν, ν = 0, 1, 2, . . . , as follows
Let T1,ν denotes the operators associated to these kernels. Then, by positivity properties
of the operator A and by Prepositions 4.2, 4.3 we obtain for
the following estimates
By summing a geometric series one sees that these estimates imply (52) and (53) for case of α = 0.
Let us first to show (60). One can check that the estimate (59) implies that the Lr norm of
is O (tn-2t -n/r). But, if we let r = n/n - 2, it is follows from Young inequality and the fact that
that
as desired. To prove the result for ν > 0, set
and let
be the kernel of the operator
. Then, if we fix x1 and y1, it follows that the
norm of the operator
equal
times the norm of the dilated operator
where δ = 2ν t-1. By Preposition 4.3, the kernel in last integral equals the complex conjugate of
and, consequently by using the Proposition 4.2, for 0 < δ ≤ ε and for supp
we obtain that
This estimate implies
Then, the desired estimate (60) follows from the above estimate and Young's inequality. The other inequality (61), follows from a similar argument.
Preposition 4.4. The estimates (32)-(34) imply (30).
Proof. Indeed, (31) implies that
and so Minkowski's inequality, (32) and (34) give that
which implies that the first inequality in (30) for sufficiently large t. Moreover, in a similar way, using (32) and (33) we get (30) for α = 0. To prove (30) for |α| = 1, we use (33), (34) and obtain
Hence, the result follows.
Now we can show the end of the proof of Theorem 4.1. Really, we obtain the estimate (30), which implies the estimates (26) and (27). That is the assertion of Theorem 4.1 is hold.
Theorem 4.2. Assume all conditions of Theorem 4.1 are satisfied, then for
if
and
then u is identically 0 if it vanishes in a nonempty open subset.
Proof. Suppose
in a connected open set G, where
and
. Then, after the possibly change of variables, one sees that Theorem 4.2 would follow
if we could show that if
then 0 ∉supp u. Moreover, by making a proper choice of geodesic coordinate system, we may assume L (x, D) as
Then argue as in [29], first set uε (x) = u (εx) where ε is chosen small enough so that (26) and (27) hold for Bε. Let
be equal to one when |x| <
and set Uε = ηuε. Then if Vε (x) = V (εx) and
which implies that
Let
If the condition (63) holds, then we can always choose δ to be small enough that
and so that if C is as in (26), (27) and C0 is as in (64) then
Next, (26), (27) imply
If we recall that
, then we see that (64) and Hölder's inequality imply
Thus, by (63) for sufficiently large t > 0 and
we can conclude that
finally, since w' (x) = 1 + x1> 0 on Bε , this forces Uε (x) = 0 for x ∈ Sδ and so 0 ∉ supp u which completes the proof.
Consider the differential operator
where aij are real-valued functions numbers, A = A (x), Ak = Ak (x), V (x) are the possible linear operators in a Banach space E.
By using Theorem 4.2 and perturbation theory of linear operators we obtain the following result
Theorem 4.3. Assume:
(1) all conditions of Theorem 4.1 are satisfied;
Then, for Dαu ∈ Lp,loc (B0; E) if ||P (x, D) u||E ≤ ||Vu||E and
, then u is identically 0 if it vanishes in a nonempty open subset.
Proof. By condition (2) and by Theorem 2.1, for all ε > 0 there is a C (ε) such that
Then, by using (29) and the above estimate we obtain the assertion.
5 Carleman estimates and unique continuation property for quasielliptic PDE
Let Ω ⊂ Rl be an open connected set with compact C2m-boundary ∂Ω. Let us consider the BVP for the following elliptic equation
Let Q denotes the operator generated by the problem (64), (65).
Theorem 5.1. Let the following conditions be satisfied;
(1)
for each |α| = 2m and
for each |α| = k < 2m with rk ≥ q and 
(2) bjβ ∈ C2m-mj (∂Ω) for each j, β and mj < 2m,
, for |β| = mj, y|∈ ∂G, where σ = (σ1, σ2, . . . , σn) ∈ Rm is a normal to ∂G ;
(4) for each y0 ∈ ∂Ω local BVP in local coordinates corresponding to y0
has a unique solution ϑ ∈C0 (R+) for all h = (h1, h2, . . . , hm) ∈ Rm, and for ξ1 ∈ Rl-1 with
(5) Condition 4.1 holds, aij ∈ C∞ (Bε), n ≥ 3,
and p' is the conjugate of p and 
(6) dk ∈ L∞ (Rn × Ω).
Then:
(a) for sufficiently large b > 0, t ≥ t0 and for
the Carleman type estimate
(b) for
and
the differential inequality
has a unique continuation property.
Proof. Let E = Lq (Ω). Consider the following operator A which is defined by
For x ∈ Rn also consider operators
The problem (5.1), (5.2) can be rewritten in the form (4.1), where u (x) = u (x, .), f (x) = f (x, .) are functions with values in E = Lq (Ω). Then by virtue of [24, Theorems 3.6 and 8.2] the (1) condition of Theorem 4.1
is satisfied. Moreover, by using the embedding
and interpolation properties of Sobolev spaces (see e.g., [19, §4]) we get that there
is ε > 0 and a continuous function C (ε) such that
Due to positive of the operator A, then we obtain that
Then it is easy to get from the above estimate that (2) condition of the Theorem 4.3 is satisfied. By virtue of (5) condition, (2) condition of the Theorem 4.1 is fulfilled too. Hence, by virtue of Theorems 4.1 and 4.3 we obtain the assertions.
6 Carleman estimates and unique continuation property for infinite systems of elliptic equations
Consider the following infinity systems of PDE
Let
Let O denotes the operator generated by the problem (66).
Theorem 6.1. Let the following conditions are satisfied:
(1) ak ∈ Cb (Rn), ak (x) ≠ 0, x ∈ Rn, k = 1, 2, . . . , n and the Condition 4.1 holds;
(2) there are 0 < ν <
such that
a.e. for x ∈ Rn.
Then:
(a) for sufficiently large b > 0, t ≥ t0 and for
the Carleman type estimate
(b) for
and
the differential inequality
has a unique continuation property.
Proof. Let E = lq and A, Ak (x) be infinite matrices, such that
It is clear to see that this operator A is R-positive in lq and all other conditions of Theorems 4.1 and 4.3 are hold. Therefore, by virtue of Theorems 4.1 and 4.3 we obtain the assertions.
Competing interests
The author declares that they have no competing interests.
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