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<art>
<ui>1687-2770-2011-10</ui>
<ji>1687-2770</ji>
<fm>
<dochead>Research</dochead>
<bibl>
<title><p>Singular limiting solutions for elliptic problem involving exponentially dominated nonlinearity and convection term</p></title>
<aug><au ca="yes" id="A1"><snm>Baraket</snm><fnm>Sami</fnm><insr iid="I1"/><email>smbaraket@yahoo.fr</email></au>
<au id="A2"><snm>Abid</snm><fnm>Imed</fnm><insr iid="I2"/><email>imed.abid@fst.rnu.tn</email></au>
<au id="A3"><snm>Ouni</snm><fnm>Taieb</fnm><insr iid="I2"/><email>Taieb.Ouni@fst.rnu.tn</email></au>
<au id="A4"><snm>Trabelsi</snm><fnm>Nihed</fnm><insr iid="I2"/><email>trabelsi.nihed@fst.rnu.tn</email></au>
</aug>
<insg>
<ins id="I1"><p>Department of Mathematics, College of Science, King Saud University, P.O. Box 2455, Riyadh 11451, Saudi Arabia</p></ins>
<ins id="I2"><p>D&#233;partement de Math&#233;matiques, Facult&#233; des Sciences de Tunis Campus Universitaire, 2092 Tunis, Tunisia</p></ins>
</insg>
<source>Boundary Value Problems</source>
<issn>1687-2770</issn>
<pubdate>2011</pubdate>
<volume>2011</volume>
<issue>1</issue>
<fpage>10</fpage>
<url>http://www.boundaryvalueproblems.com/content/2011/1/10</url>
<xrefbib><pubid idtype="doi">10.1186/1687-2770-2011-10</pubid></xrefbib></bibl>
<history><rec><date><day>22</day><month>3</month><year>2011</year></date></rec><acc><date><day>12</day><month>8</month><year>2011</year></date></acc><pub><date><day>12</day><month>8</month><year>2011</year></date></pub></history><cpyrt><year>2011</year><collab>Baraket et al; licensee Springer.</collab><note>This is an Open Access article distributed under the terms of the Creative Commons Attribution License (<url>http://creativecommons.org/licenses/by/2.0</url>), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.</note></cpyrt>
<kwdg>
<kwd>singular limits</kwd><kwd>Green's function</kwd><kwd>nonlinear Cauchy-data matching method</kwd>
</kwdg>
<abs>
<sec><st><p>Abstract</p></st>
<p>Given &#937; bounded open regular set of &#8477;<sup>2 </sup>and <it>x</it><sub>1</sub>, <it>x</it><sub>2</sub>, ..., <it>x<sub>m </sub></it>&#8712; &#937;, we give a sufficient condition for the problem</p>
<p><display-formula><graphic file="1687-2770-2011-10-i1.gif"/></display-formula></p>
<p>to have a positive weak solution in &#937; with <it>u </it>= 0 on &#8706;&#937;, which is singular at each <it>x<sub>i </sub></it>as the parameters <it>&#961;</it>, <it>&#955; </it>&gt; 0 tend to 0 and where <it>f</it>(<it>u</it>) is dominated exponential nonlinearities functions.</p>
<p>2000 <b>Mathematics Subject Classification</b>: 35J60; 53C21; 58J05.</p>
</sec>
</abs>
</fm>
<bdy>
<sec><st><p>1 Introduction and statement of the results</p></st>
<p>We consider the following problem</p>
<p><display-formula id="M1"><graphic file="1687-2770-2011-10-i2.gif"/></display-formula></p>
<p>where &#8711; is the gradient and &#937; is an open smooth bounded subset of &#8477;<sup>2</sup>. The function <it>a </it>is assumed to be positive and smooth. In the following, we take <it>a</it>(<it>u</it>) = <it>e<sup>&#955;u </sup></it>and <it>f</it>(<it>u</it>) = <it>e<sup>&#955;u</sup></it>(<it>e<sup>u </sup></it>+ <it>e<sup>&#947;u</sup></it>), for <it>&#955; </it>&gt; 0 and <it>&#947; </it>&#8712;(0, 1), then problem (1) take the form</p>
<p><display-formula id="M2"><graphic file="1687-2770-2011-10-i3.gif"/></display-formula></p>
<p>Using the following transformation</p>
<p><display-formula><graphic file="1687-2770-2011-10-i4.gif"/></display-formula></p>
<p>then the function <it>w </it>satisfies the following problem</p>
<p><display-formula id="M3"><graphic file="1687-2770-2011-10-i5.gif"/></display-formula></p>
<p>with &#1009; = (<it>&#955;&#961;</it><sup>2</sup>)<sup>1-<it>&#955;</it></sup>. So when <it>&#955; </it>&#8594; 0<sup>+</sup>, the exponent <inline-formula><graphic file="1687-2770-2011-10-i6.gif"/></inline-formula> tends to infinity while the exponent <inline-formula><graphic file="1687-2770-2011-10-i7.gif"/></inline-formula> tends to -&#8734;. For &#1009; &#8801; 0, problem (3) has been studied by Ren and Wei in <abbrgrp><abbr bid="B1">1</abbr></abbrgrp>. See also <abbrgrp><abbr bid="B2">2</abbr></abbrgrp>.</p>
<p>We denote by <it>&#949; </it>the smallest positive parameter satisfying</p>
<p><display-formula id="M4"><graphic file="1687-2770-2011-10-i8.gif"/></display-formula></p>
<p>Remark that <it>&#961; </it>~ <it>&#949; </it>as <it>&#949; </it>&#8594; 0. We will suppose in the following</p>
<p><display-formula><graphic file="1687-2770-2011-10-i9.gif"/></display-formula></p>
<p>In particular, if we take <inline-formula><graphic file="1687-2770-2011-10-i10.gif"/></inline-formula>, then the condition (<it>A<sub>&#955;</sub></it>) is satisfied. Under the assumption (<it>A<sub>&#955;</sub></it>), we can treat equation (2) as a perturbation of the following:</p>
<p><display-formula><graphic file="1687-2770-2011-10-i11.gif"/></display-formula></p>
<p>for <it>&#947; </it>&#8712; (0, 1).</p>
<p>Our question is: Does there exist <it>v</it><sub><it>&#949;</it>,<it>&#955; </it></sub>a sequence of solutions of (2) which converges to some singular function as the parameters <it>&#949; </it>and <it>&#955; </it>tend to 0?</p>
<p>In <abbrgrp><abbr bid="B3">3</abbr></abbrgrp>, Baraket et al. gave a positive answer to the above question for the following problem</p>
<p><display-formula id="M5"><graphic file="1687-2770-2011-10-i12.gif"/></display-formula></p>
<p>with a regular bounded domain &#937; of &#8477;<sup>2</sup>. They give a sufficient condition for the problem (5) to have a weak solution in &#937; which is singular at some points (<it>x<sub>i</sub></it>)<sub>1&#8804;<it>i</it>&#8804;<it>m </it></sub>as <it>&#961; </it>and <it>&#955; </it>a small parameters satisfying (<it>A<sub>&#955;</sub></it>), where the presence of the gradient term seems to have significant influence on the existence of such solutions, as well as on their asymptotic behavior.</p>
<p>In case <it>&#955; </it>= 0 the authors in <abbrgrp><abbr bid="B4">4</abbr></abbrgrp> gave also a positive answer for the following problem</p>
<p><display-formula id="M6"><graphic file="1687-2770-2011-10-i13.gif"/></display-formula></p>
<p>for <it>&#947; </it>&#8712; (0, 1) as <it>&#961; </it>tends to 0. When <it>&#955; </it>= 0 and <it>&#947; </it>= 0, problem (2) reduce to</p>
<p><display-formula id="M7"><graphic file="1687-2770-2011-10-i14.gif"/></display-formula></p>
<p>The study of this problem goes back to 1853 when Liouville derived a representation formula for all solutions of (7) which are defined in &#8477;<sup>2</sup>, see <abbrgrp><abbr bid="B5">5</abbr></abbrgrp>. It turns out that, beside the applications in geometry, elliptic equations with exponential nonlinearity also arise in modeling many physical phenomenon, such as thermionic emission, isothermal gas sphere, gas combustion, and gauge theory <abbrgrp><abbr bid="B6">6</abbr></abbrgrp>. When <it>&#961; </it>tends to 0, the asymptotic behavior of nontrivial branches of solutions of (7) is well understood thanks to the pioneer work of Suzuki <abbrgrp><abbr bid="B7">7</abbr></abbrgrp> which characterizes the possible limit of nontrivial branches of solutions of (7). His result has been generalized in <abbrgrp><abbr bid="B8">8</abbr></abbrgrp> to (6) with <inline-formula><graphic file="1687-2770-2011-10-i15.gif"/></inline-formula>, and finally by Ye in <abbrgrp><abbr bid="B9">9</abbr></abbrgrp> to any exponentially dominated nonlinearity <it>f</it>(<it>u</it>). The existence of nontrivial branches of solutions with single singularity was first proved by Weston <abbrgrp><abbr bid="B10">10</abbr></abbrgrp> and then a general result has been obtained by Baraket and Pacard <abbrgrp><abbr bid="B11">11</abbr></abbrgrp>. These results were also extended, applying to the Chern-Simons vortex theory in mind, by Esposito et al. <abbrgrp><abbr bid="B12">12</abbr></abbrgrp> and Del Pino et al. <abbrgrp><abbr bid="B13">13</abbr></abbrgrp> to handle equations of the form -&#916;<it>u </it>= <it>&#961;</it><sup>2</sup><it>V</it>(<it>x</it>)<it>e<sup>u </sup></it>where <it>V </it>is a nonconstant positive potential. See also <abbrgrp><abbr bid="B14">14</abbr><abbr bid="B15">15</abbr><abbr bid="B16">16</abbr></abbrgrp> wherever this rule is applicable. where the Laplacian is replaced by a more general divergence operator and some new phenomena occur. Let us also mention that the construction of nontrivial branches of solutions of semilinear equations with exponential nonlinearities allowed Wente to provide counter examples to a conjecture of Hopf <abbrgrp><abbr bid="B17">17</abbr></abbrgrp> concerning the existence of compact (immersed) constant mean curvature surfaces in Euclidean space. Another related problem is the higher dimension problem with exponential nonlinearity. For example, the 4-dimensional semilinear elliptic problem with bi-Laplacian is treated in <abbrgrp><abbr bid="B18">18</abbr></abbrgrp> and the problem with an additional singular source term given by Dirac masses is treated in <abbrgrp><abbr bid="B19">19</abbr></abbrgrp> in the radial case. The results in <abbrgrp><abbr bid="B18">18</abbr><abbr bid="B19">19</abbr></abbrgrp> are generalized to noncritical points of the reduced function, see <abbrgrp><abbr bid="B20">20</abbr></abbrgrp>.</p>
<p>We introduce now the Green's function <it>G</it>(<it>x</it>, <it>x</it>') defined on &#937; &#215; &#937;, to be solution of</p>
<p><display-formula><graphic file="1687-2770-2011-10-i16.gif"/></display-formula></p>
<p>and let <it>H</it>(<it>x</it>, <it>x</it>') = <it>G</it>(<it>x</it>, <it>x</it>') + 4log |<it>x </it>- <it>x</it>'|, its regular part. Let <it>m </it>&#8712; &#8469;, we set</p>
<p><display-formula id="M8"><graphic file="1687-2770-2011-10-i17.gif"/></display-formula></p>
<p>which is well defined in (&#937;)<it><sup>m </sup></it>for <it>x<sub>i </sub></it>&#8800; <it>x<sub>j </sub></it>for <it>i </it>&#8800; <it>j</it>. Our main result is the following</p>
<p><b>Theorem 1 </b><it>Given &#946; </it>&#8712; (0, 1)<it>. Let </it>&#937; <it>an open smooth bounded set of </it>&#8477;<sup>2</sup><it>, &#955; </it>&gt; 0 <it>satisfying the condition </it>(<it>A<sub>&#955;</sub></it>)<it>, &#947; </it>&#8712; (0, 1) <it>and S </it>= {<it>x</it><sub>1</sub>, ... <it>x<sub>m</sub></it>} &#8834; &#937; <it>be a nonempty set. Assume that, the point </it>(<it>x</it><sub>1</sub>, ..., <it>x<sub>m</sub></it>) <it>is a </it>nondegenerate <it>critical point of the function</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i18.gif"/></display-formula></p>
<p><it>then there exist &#949;</it><sub>0 </sub>&gt; 0, <it>&#955;</it><sub>0 </sub>&gt; 0 <it>and </it><inline-formula><graphic file="1687-2770-2011-10-i19.gif"/></inline-formula> <it>a family of solutions of (2), such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i20.gif"/></display-formula></p>
<p>One of the purpose of the present paper is to present a rather efficient method: <it>nonlinear Cauchy-data matching method </it>to solve such singularly problems. This method has already been used successfully in geometric context (constant mean curvature surfaces, constant scalar curvature metrics, extremal K&#228;hler metrics, manifolds with special holonomy, ...) and appeared in the study <abbrgrp><abbr bid="B18">18</abbr></abbrgrp> in the context of partial differential equations.</p>
</sec>
<sec><st><p>2 Construction of the approximate solution</p></st>
<p>We first describe the rotationally symmetric approximate solutions of</p>
<p><display-formula id="M9"><graphic file="1687-2770-2011-10-i21.gif"/></display-formula></p>
<p>in &#8477;<sup>2 </sup>which will play a central role in our analysis. Given <it>&#949; </it>&gt; 0, we define</p>
<p><display-formula id="M10"><graphic file="1687-2770-2011-10-i22.gif"/></display-formula></p>
<p>which is clearly a solution of</p>
<p><display-formula id="M11"><graphic file="1687-2770-2011-10-i23.gif"/></display-formula></p>
<p>in &#8477;<sup>2</sup>. Let us notice that equations (11) is invariant under dilation in the following sense: If <it>v </it>is a solution of (11) and if <it>&#964; </it>&gt; 0, then <it>v</it>(<it>&#964; </it>&#183;) + 2log<it>&#964; </it>is also a solution of (11). With this observation in mind, we define for all <it>&#964; </it>&gt; 0</p>
<p><display-formula id="M12"><graphic file="1687-2770-2011-10-i24.gif"/></display-formula></p>
<sec><st><p>2.1 A linearized operator on &#8477;<sup>2</sup></p></st>
<p>For all <it>&#949;</it>, <it>&#964;</it>, <it>&#955; </it>&gt; 0, we set</p>
<p><display-formula id="M13"><graphic file="1687-2770-2011-10-i25.gif"/></display-formula></p>
<p>for <it>&#948; </it>&#8712; (0, 1). We define the linear second order elliptic operator</p>
<p><display-formula id="M14"><graphic file="1687-2770-2011-10-i26.gif"/></display-formula></p>
<p>which corresponds to the linearization of (11) about the solution <it>u</it><sub>1 </sub>(= <it>u</it><sub><it>&#949; </it>= <it>&#964; </it>= 1</sub>) given by (10) which has been defined in the previous section. We are interested in the classification of bounded solutions of <inline-formula><graphic file="1687-2770-2011-10-i27.gif"/></inline-formula> in &#8477;<sup>2</sup>. Some solutions are easy to find. For example, we can define</p>
<p><display-formula><graphic file="1687-2770-2011-10-i28.gif"/></display-formula></p>
<p>where <it>r </it>= |<it>x</it>|. Clearly <inline-formula><graphic file="1687-2770-2011-10-i29.gif"/></inline-formula> and this reflects the fact that (11) is invariant under the group of dilations <it>&#964; </it>&#8594; <it>u</it>(<it>&#964; </it>&#183;) + 2 log<it>&#964;</it>. We also define, for <it>i </it>= 1, 2</p>
<p><display-formula><graphic file="1687-2770-2011-10-i30.gif"/></display-formula></p>
<p>which are also solutions of <inline-formula><graphic file="1687-2770-2011-10-i31.gif"/></inline-formula>. Since, these solutions correspond to the invariance of the equation under the group of translations <it>a </it>&#8594; <it>u</it>(&#183; + <it>a</it>). We recall the following result which classifies all bounded solutions of <inline-formula><graphic file="1687-2770-2011-10-i27.gif"/></inline-formula> which are defined in &#8477;<sup>2</sup>.</p>
<p><b>Lemma 1 </b><abbrgrp><abbr bid="B11">11</abbr></abbrgrp> <it>Any bounded solution of </it><inline-formula><graphic file="1687-2770-2011-10-i27.gif"/></inline-formula> <it>defined in </it>&#8477;<sup>2 </sup><it>is a linear combination of &#981;<sub>i </sub>for i </it>= 0, 1, 2.</p>
<p>Let <it>B<sub>r </sub></it>denote the ball of radius <it>r </it>centered at the origin in &#8477;<sup>2</sup>.</p>
<p><b>Definition 1 </b><it>Given k </it>&#8712; &#8469;<it>, &#946; </it>&#8712; (0, 1) <it>and &#956; </it>&#8712; &#8477;<it>, we introduce the H&#246;lder weighted spaces <inline-formula><graphic file="1687-2770-2011-10-i32.gif"/></inline-formula> as the space of functions <inline-formula><graphic file="1687-2770-2011-10-i33.gif"/></inline-formula> for which the following norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i34.gif"/></display-formula></p>
<p><it>is finite</it>.</p>
<p>We define also</p>
<p><display-formula><graphic file="1687-2770-2011-10-i35.gif"/></display-formula></p>
<p>As a consequence of the result of Lemma 1, we recall the surjectivity result of <inline-formula><graphic file="1687-2770-2011-10-i36.gif"/></inline-formula> given in <abbrgrp><abbr bid="B11">11</abbr></abbrgrp>.</p>
<p><b>Proposition 1 </b><abbrgrp><abbr bid="B11">11</abbr></abbrgrp></p>
<p>(i) <it>Assume that &#956; </it>&gt; 1 <it>and &#956; </it>&#8713; &#8469;<it>, then</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i37.gif"/></display-formula></p>
<p><it>is surjective</it>.</p>
<p>(ii) <it>Assume that &#948; </it>&gt; 0 <it>and &#948; </it>&#8713; &#8469; <it>then</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i38.gif"/></display-formula></p>
<p><it>is surjective</it>.</p>
<p>We set <inline-formula><graphic file="1687-2770-2011-10-i39.gif"/></inline-formula>, we define</p>
<p><b>Definition 2 </b><it>Given k </it>&#8712; &#8469;<it>, &#946; </it>&#8712; (0, 1) <it>and &#956; </it>&#8712; &#8477;<it>, we introduce the H&#246;lder weighted spaces <inline-formula><graphic file="1687-2770-2011-10-i40.gif"/></inline-formula> as the space of functions in <inline-formula><graphic file="1687-2770-2011-10-i41.gif"/></inline-formula> for which the following norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i42.gif"/></display-formula></p>
<p><it>is finite</it>.</p>
<p>Then, we define the subspace of radial functions in <inline-formula><graphic file="1687-2770-2011-10-i43.gif"/></inline-formula> by</p>
<p><display-formula><graphic file="1687-2770-2011-10-i44.gif"/></display-formula></p>
<p>We would like to find a solution <it>u </it>of</p>
<p><display-formula id="M15"><graphic file="1687-2770-2011-10-i45.gif"/></display-formula></p>
<p>in <inline-formula><graphic file="1687-2770-2011-10-i46.gif"/></inline-formula>. By using the transformation, <inline-formula><graphic file="1687-2770-2011-10-i47.gif"/></inline-formula> then Eq. (15) is equivalent to</p>
<p><display-formula id="M16"><graphic file="1687-2770-2011-10-i48.gif"/></display-formula></p>
<p>in <inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula>. We look for a solution of (16) of the form <it>v</it>(<it>x</it>) = <it>u</it><sub>1</sub>(<it>x</it>) + <it>h</it>(<it>x</it>), this amounts to solve</p>
<p><display-formula id="M17"><graphic file="1687-2770-2011-10-i50.gif"/></display-formula></p>
<p>In <inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula>. We will need the following:</p>
<p><b>Definition 3 </b><it>Given <inline-formula><graphic file="1687-2770-2011-10-i51.gif"/></inline-formula>, k </it>&#8712; &#8734;<it>, &#946; </it>&#8712; (0, 1) <it>and &#956; </it>&#8712; &#8477;<it>, the weighted space <inline-formula><graphic file="1687-2770-2011-10-i52.gif"/></inline-formula> is defined to be the space of functions <inline-formula><graphic file="1687-2770-2011-10-i53.gif"/></inline-formula> endowed with the norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i54.gif"/></display-formula></p>
<p>For all <it>&#963; </it>&#8805; 1, we denote by <inline-formula><graphic file="1687-2770-2011-10-i55.gif"/></inline-formula> the extension operator defined by</p>
<p><display-formula id="M18"><graphic file="1687-2770-2011-10-i56.gif"/></display-formula></p>
<p>where <it>t </it>&#945; <it>&#967;</it>(<it>t</it>) is a smooth non-negative cutoff function identically equal to 1 for <it>t </it>&#8804; 1 and identically equal to 0 for <it>t </it>&#8805; 2. It is easy to check that there exists a constant <it>c </it>= <it>c</it>(<it>&#956;</it>) &gt; 0, independent of <it>&#963; </it>&#8805; 1, such that</p>
<p><display-formula id="M19"><graphic file="1687-2770-2011-10-i57.gif"/></display-formula></p>
<p>We fix <it>&#948; </it>&#8712; (0, 1) and denote by <inline-formula><graphic file="1687-2770-2011-10-i58.gif"/></inline-formula> to be a right inverse of <inline-formula><graphic file="1687-2770-2011-10-i59.gif"/></inline-formula> provided by Proposition 1. To find a solution of (17), it is enough to find a fixed point <it>h</it>, in a small ball of <inline-formula><graphic file="1687-2770-2011-10-i60.gif"/></inline-formula>, solution of</p>
<p><display-formula id="M20"><graphic file="1687-2770-2011-10-i61.gif"/></display-formula></p>
<p>We have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i62.gif"/></display-formula></p>
<p>This implies that given <it>&#954; </it>&gt; 0, there exist <it>c<sub>&#954; </sub>&gt; </it>0 (only depend on <it>&#954;</it>), such that for <it>&#948; </it>&#8712; (0,1) and |<it>x| </it>= <it>r</it>, we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i63.gif"/></display-formula></p>
<p>Making use of Proposition 1 together with (19), we conclude that</p>
<p><display-formula id="M21"><graphic file="1687-2770-2011-10-i64.gif"/></display-formula></p>
<p>Now, let <it>h</it><sub>1</sub>, <it>h</it><sub>2 </sub>such that <inline-formula><graphic file="1687-2770-2011-10-i65.gif"/></inline-formula> in <inline-formula><graphic file="1687-2770-2011-10-i60.gif"/></inline-formula>, then for <it>&#948; </it>&#8712; (0, 1 - <it>r</it>] we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i66.gif"/></display-formula></p>
<p>Similarly, making use of Proposition 1 together with condition (<it>A<sub>&#955;</sub></it>) and (19), we conclude that given <it>&#954; </it>&gt; 0, there exist <it>&#949;</it><sub><it>&#954; </it></sub>&gt; 0, <it>&#955;</it><sub><it>&#954; </it></sub>&gt; 0 and <inline-formula><graphic file="1687-2770-2011-10-i67.gif"/></inline-formula> (only depend on <it>&#954;</it>) such that</p>
<p><display-formula id="M22"><graphic file="1687-2770-2011-10-i68.gif"/></display-formula></p>
<p>Reducing <it>&#955;</it><sub><it>&#954; </it></sub>&gt; 0 and <it>&#949;</it><sub><it>&#954; </it></sub>&gt; 0 if necessary, we can assume that, <inline-formula><graphic file="1687-2770-2011-10-i69.gif"/></inline-formula> for all <it>&#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>) and <it>&#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>). Then, (21) and (22) are enough to show that <it>h </it>&#8614; &#8501; is a contraction from <inline-formula><graphic file="1687-2770-2011-10-i70.gif"/></inline-formula> into itself and hence has a unique fixed point <it>h </it>in this set. This fixed point is solution of (20) in <inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula>. We summarize this in the:</p>
<p><b>Proposition 2 </b><it>Given &#948; </it>&#8712; (0, 1 - <it>&#947;</it>] <it>and &#954; </it>&gt; 1, <it>then there exist <inline-formula><graphic file="1687-2770-2011-10-i71.gif"/></inline-formula> (independent of &#949; and &#955;) and a unique <inline-formula><graphic file="1687-2770-2011-10-i72.gif"/></inline-formula> with <inline-formula><graphic file="1687-2770-2011-10-i73.gif"/></inline-formula> such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i74.gif"/></display-formula></p>
<p><it>solves (16) in </it><inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula>.</p>
</sec>
<sec><st><p>2.2 Analysis of the Laplace operator in weighted spaces</p></st>
<p>In this section, we study the mapping properties of the Laplace operator in weighted H&#246;lder spaces. Given <it>x</it><sub>1</sub>, ..., <it>x<sub>m </sub></it>&#8712; &#937;, we define <b>x </b>:= (<it>x</it><sub>1</sub>, ..., <it>x<sub>m</sub></it>)</p>
<p><display-formula><graphic file="1687-2770-2011-10-i75.gif"/></display-formula></p>
<p>and we choose <it>r</it><sub>0 </sub>&gt; 0 so that the balls <inline-formula><graphic file="1687-2770-2011-10-i76.gif"/></inline-formula> of center <it>x<sub>i </sub></it>and radius <it>r</it><sub>0 </sub>are mutually disjoint and included in &#937;. For all <it>r </it>&#8712; (0, <it>r</it><sub>0</sub>), we define</p>
<p><display-formula><graphic file="1687-2770-2011-10-i77.gif"/></display-formula></p>
<p>With these notations, we have:</p>
<p><b>Definition 4 </b><it>Given k </it>&#8712; &#8477;, <it>&#946; </it>&#8712; (0,1) <it>and &#957; </it>&#8712; &#8477;, <it>we introduce the H&#246;lder weighted space <inline-formula><graphic file="1687-2770-2011-10-i78.gif"/></inline-formula> as the space of functions <inline-formula><graphic file="1687-2770-2011-10-i79.gif"/></inline-formula> for with the following norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i80.gif"/></display-formula></p>
<p><it>is finite</it>.</p>
<p>When <it>k </it>&#8805; 2, we denote by <inline-formula><graphic file="1687-2770-2011-10-i81.gif"/></inline-formula> be the subspace of functions <inline-formula><graphic file="1687-2770-2011-10-i82.gif"/></inline-formula> satisfying <it>w </it>= 0 on &#8706;&#937;. We recall the</p>
<p><b>Proposition 3 </b><abbrgrp><abbr bid="B21">21</abbr></abbrgrp> <it>Assume that &#957; </it>&lt; 0 <it>and &#957; &#8713; &#8484;, then</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i83.gif"/></display-formula></p>
<p><it>is surjective. Denote by </it><inline-formula><graphic file="1687-2770-2011-10-i84.gif"/></inline-formula> <it>a right inverse of </it><inline-formula><graphic file="1687-2770-2011-10-i85.gif"/></inline-formula>.</p>
<p><b>Remark 1 </b><it>Observe that, when &#957; </it>&lt; 0, <it>&#957; &#8713; &#8484;, the right inverse even though is not unique and can be chosen to depend smoothly on the points x</it><sub>1</sub>, ..., <it>x<sub>m</sub>, at least locally. Once a right inverse is fixed for some choice of the points x</it><sub>1</sub>, ..., <it>x<sub>m</sub>, a right inverse which depends smoothly on some points <inline-formula><graphic file="1687-2770-2011-10-i86.gif"/></inline-formula> close to x</it><sub>1</sub>, ..., <it>x<sub>m </sub>can be obtained using a simple perturbation argument. This argument will be used later in the nonlinear exterior problem, since we will move a little bit the points </it>(<it>x<sub>i</sub></it>).</p>
</sec>
<sec><st><p>2.3 Harmonic extensions</p></st>
<p>We study the properties of interior and exterior harmonic extensions. Given <inline-formula><graphic file="1687-2770-2011-10-i87.gif"/></inline-formula> and define <it>H<sup>i </sup></it>(=<it>H<sup>i </sup></it>(<it>&#966;</it>; &#183;)) to be the solution of</p>
<p><display-formula id="M23"><graphic file="1687-2770-2011-10-i88.gif"/></display-formula></p>
<p>We denote by <it>e</it><sub>1</sub>, <it>e</it><sub>2 </sub>the coordinate functions on <it>S</it><sup>1</sup>.</p>
<p><b>Lemma 2 </b><abbrgrp><abbr bid="B21">21</abbr></abbrgrp> <it>If we assume that</it></p>
<p><display-formula id="M24"><graphic file="1687-2770-2011-10-i89.gif"/></display-formula></p>
<p><it>then there exists c </it>&gt; 0 <it>such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i90.gif"/></display-formula></p>
<p>Given <inline-formula><graphic file="1687-2770-2011-10-i91.gif"/></inline-formula>, we define <inline-formula><graphic file="1687-2770-2011-10-i92.gif"/></inline-formula> to be the solution of</p>
<p><display-formula id="M25"><graphic file="1687-2770-2011-10-i93.gif"/></display-formula></p>
<p>which decays at infinity.</p>
<p><b>Definition 5 </b><it>Given k </it>&#8712; &#8469;, <it>&#946; </it>&#8712; (0,1) <it>and &#957; </it>&#8712; &#8477;<it>, we define the space <inline-formula><graphic file="1687-2770-2011-10-i94.gif"/></inline-formula> as the space of functions <inline-formula><graphic file="1687-2770-2011-10-i95.gif"/></inline-formula> for which the following norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i96.gif"/></display-formula></p>
<p><it>is finite</it>.</p>
<p><b>Lemma 3 </b><abbrgrp><abbr bid="B21">21</abbr></abbrgrp> <it>If we assume that</it></p>
<p><display-formula id="M26"><graphic file="1687-2770-2011-10-i97.gif"/></display-formula></p>
<p><it>Then there exists c </it>&gt; 0 <it>such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i98.gif"/></display-formula></p>
<p>If <it>F </it>&#8834; <it>L</it><sup>2</sup>(<it>S</it><sup>1</sup>) is a space of functions defined on <it>S</it><sup>1</sup>, we define the space <it>F</it><sub>&#8869; </sub>to be the subspace of functions <it>F </it>of which are <it>L</it><sup>2</sup>(<it>S</it><sup>1</sup>) -orthogonal to the functions 1, <it>e</it><sub>1</sub>,<it>e</it><sub>2</sub>. We will need the:</p>
<p><b>Lemma 4 </b><abbrgrp><abbr bid="B21">21</abbr></abbrgrp> <it>The mapping</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i99.gif"/></display-formula></p>
<p><it>where H<sup>i</sup></it>(= <it>H<sup>i </sup></it>(<it>&#968;</it>; &#183;)) <it>and H<sup>e </sup></it>= <it>H<sup>e</sup></it>(<it>&#968;</it>; &#183;), <it>is an isomorphism</it>.</p>
</sec>
</sec>
<sec><st><p>3 The nonlinear interior problem</p></st>
<p>We are interested in studying equations of type</p>
<p><display-formula id="M27"><graphic file="1687-2770-2011-10-i100.gif"/></display-formula></p>
<p>In <inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula>.</p>
<p>Given <inline-formula><graphic file="1687-2770-2011-10-i101.gif"/></inline-formula> satisfying (24), we define</p>
<p><display-formula><graphic file="1687-2770-2011-10-i102.gif"/></display-formula></p>
<p>Then, we look for a solution of (27) of the form <it>w </it>= <b>v </b>+ <it>v </it>and using the fact that <it>H<sup>i </sup></it>is harmonic, this amounts to solve</p>
<p><display-formula id="M28"><graphic file="1687-2770-2011-10-i103.gif"/></display-formula></p>
<p>We fix <it>&#956; </it>&#8712; (1,2) and denote by <inline-formula><graphic file="1687-2770-2011-10-i104.gif"/></inline-formula> to be a right inverse of <inline-formula><graphic file="1687-2770-2011-10-i105.gif"/></inline-formula> provided by Proposition 1. To find a solution of (28), it is sufficient to find <inline-formula><graphic file="1687-2770-2011-10-i106.gif"/></inline-formula> solution of</p>
<p><display-formula id="M29"><graphic file="1687-2770-2011-10-i107.gif"/></display-formula></p>
<p>We denote by <inline-formula><graphic file="1687-2770-2011-10-i108.gif"/></inline-formula>, the nonlinear operator appearing on the right-hand side of equation (29).</p>
<p>Given <it>&#954; </it>&gt; 0 (whose value will be fixed later on), we further assume that the functions <it>&#966; </it>satisfy</p>
<p><display-formula id="M30"><graphic file="1687-2770-2011-10-i109.gif"/></display-formula></p>
<p>Then, we have the following result</p>
<p><b>Lemma 5 </b><it>Given &#954; </it>&gt; 0. <it>There exist &#949;<sub>&#954; </sub></it>&gt; 0, <it>&#955;<sub>&#954; </sub></it>&gt; 0, <it>c<sub>&#954; </sub></it>&gt; 0 <it>and </it><inline-formula><graphic file="1687-2770-2011-10-i71.gif"/></inline-formula> <it>(only depend on &#954;) such that for all &#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>) <it>and &#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>)</p>
<p><display-formula><graphic file="1687-2770-2011-10-i110.gif"/></display-formula></p>
<p><it>and</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i111.gif"/></display-formula></p>
<p><it>provided </it><inline-formula><graphic file="1687-2770-2011-10-i112.gif"/></inline-formula> <it>satisfying </it><inline-formula><graphic file="1687-2770-2011-10-i113.gif"/></inline-formula>.</p>
<p><it>Proof</it>. The proof of the first estimate follows from the asymptotic behavior of <it>H<sup>i </sup></it>together with the assumption on the norm of boundary data <it>&#966; </it>given by (30). Indeed, let <it>c<sub>&#954; </sub></it>be a constant depending only on <it>&#954; </it>(provided <it>&#949; </it>and <it>&#955; </it>are chosen small enough) it follows from the estimate of <it>H<sup>i</sup></it>, given by lemma 2, that</p>
<p><display-formula><graphic file="1687-2770-2011-10-i114.gif"/></display-formula></p>
<p>Since for each <inline-formula><graphic file="1687-2770-2011-10-i115.gif"/></inline-formula>, we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i116.gif"/></display-formula></p>
<p>where <it>&#948; </it>&#8712; (0, 1 - <it>&#947;</it>]. Then</p>
<p><display-formula><graphic file="1687-2770-2011-10-i117.gif"/></display-formula></p>
<p>On the other hand, using the condition (<it>A<sub>&#955;</sub></it>), we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i118.gif"/></display-formula></p>
<p>and</p>
<p><display-formula><graphic file="1687-2770-2011-10-i119.gif"/></display-formula></p>
<p>Making use of Proposition 1 together with (20), we get</p>
<p><display-formula id="M31"><graphic file="1687-2770-2011-10-i120.gif"/></display-formula></p>
<p>In order to derive the second estimate, we use the fact that, for <inline-formula><graphic file="1687-2770-2011-10-i112.gif"/></inline-formula> satisfying <inline-formula><graphic file="1687-2770-2011-10-i121.gif"/></inline-formula> for <it>i </it>= 1,2, <it>&#956; </it>&#8712; (1,2) and the condition (<it>A<sub>&#955;</sub></it>), then there exist <it>c<sub>&#954; </sub>&gt; </it>0 (only depend on <it>&#954;</it>) such that</p>
<p><display-formula><graphic file="1687-2770-2011-10-i122.gif"/></display-formula></p>
<p>Similarly, making use of Proposition 1 together with (19), we conclude that there exists <inline-formula><graphic file="1687-2770-2011-10-i71.gif"/></inline-formula> (only depend on <it>&#954;</it>) such that</p>
<p><display-formula id="M32"><graphic file="1687-2770-2011-10-i123.gif"/></display-formula></p>
<p>&#9633;</p>
<p>Reducing <it>&#955;</it><sub><it>&#954; </it></sub>&gt; 0 and <it>&#949;</it><sub><it>&#954; </it></sub>&gt; 0 if necessary, we can assume that, <inline-formula><graphic file="1687-2770-2011-10-i124.gif"/></inline-formula> for all <it>&#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>) and <it>&#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>). Then, (31) and (32) are enough to show that <inline-formula><graphic file="1687-2770-2011-10-i125.gif"/></inline-formula> is a contraction from <inline-formula><graphic file="1687-2770-2011-10-i126.gif"/></inline-formula> into itself and hence has a unique fixed point <inline-formula><graphic file="1687-2770-2011-10-i127.gif"/></inline-formula> in this set. This fixed point is solution of (20) in &#8477;<sup>2</sup>. We summarize this in the following:</p>
<p><b>Proposition 4 </b><it>Given &#954; &gt; </it>0, <it>there exist &#949;<sub>&#954; </sub>&gt; </it>0, <it>&#955;<sub>&#954; </sub>&gt; </it>0 <it>and c<sub>&#954; </sub>&gt; </it>0 <it>(only depending on &#954;) such that for all &#949; </it>&#8712; (0, <it>&#949;<sub>&#954; </sub></it>)<it>, &#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>) <it>satisfying </it>(<it>A</it>)<it>, for all &#964; in some fixed compact subset of </it>[<it>&#964; -</it>, <it>&#964;</it><sup>+</sup>] &#8834; (0, &#8734;) <it>and for a given &#966; satisfying (24)-(30), then there exists a unique </it><inline-formula><graphic file="1687-2770-2011-10-i128.gif"/></inline-formula> <it>solution of (29) such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i129.gif"/></display-formula></p>
<p><it>Solve </it>(27) <it>in </it><inline-formula><graphic file="1687-2770-2011-10-i49.gif"/></inline-formula><it>. In addition</it>,</p>
<p><display-formula><graphic file="1687-2770-2011-10-i130.gif"/></display-formula></p>
<p>Observe that the function <inline-formula><graphic file="1687-2770-2011-10-i128.gif"/></inline-formula> being obtained as a fixed point for contraction mappings, it depends continuously on the parameter <it>&#964;</it>.</p>
</sec>
<sec><st><p>4 The nonlinear exterior problem</p></st>
<p>Recall that <inline-formula><graphic file="1687-2770-2011-10-i131.gif"/></inline-formula> denote the unique solution of</p>
<p><display-formula><graphic file="1687-2770-2011-10-i132.gif"/></display-formula></p>
<p>in &#937;, with <inline-formula><graphic file="1687-2770-2011-10-i133.gif"/></inline-formula> on &#8706;&#937;. In addition, the following decomposition holds</p>
<p><display-formula><graphic file="1687-2770-2011-10-i134.gif"/></display-formula></p>
<p>where <inline-formula><graphic file="1687-2770-2011-10-i135.gif"/></inline-formula> is a smooth function. Here, we give an estimate of the gradient of <inline-formula><graphic file="1687-2770-2011-10-i136.gif"/></inline-formula> without proof (see <abbrgrp><abbr bid="B14">14</abbr></abbrgrp>, Lemma 2.1), there exists a constant <it>c &gt; </it>0, so that</p>
<p><display-formula><graphic file="1687-2770-2011-10-i137.gif"/></display-formula></p>
<p>Let <inline-formula><graphic file="1687-2770-2011-10-i138.gif"/></inline-formula> close enough to <b>x </b>:= (<it>x</it><sub>1</sub>, ..., <it>x<sub>m</sub></it>), <inline-formula><graphic file="1687-2770-2011-10-i139.gif"/></inline-formula> close to 0 and <inline-formula><graphic file="1687-2770-2011-10-i140.gif"/></inline-formula> satisfying (26). We define</p>
<p><display-formula id="M33"><graphic file="1687-2770-2011-10-i141.gif"/></display-formula></p>
<p>where <inline-formula><graphic file="1687-2770-2011-10-i142.gif"/></inline-formula> is a cutoff function identically equal to 1 in <inline-formula><graphic file="1687-2770-2011-10-i143.gif"/></inline-formula> and identically equal to 0 outside <inline-formula><graphic file="1687-2770-2011-10-i144.gif"/></inline-formula>.</p>
<p>We would like to find a solution of</p>
<p><display-formula id="M34"><graphic file="1687-2770-2011-10-i145.gif"/></display-formula></p>
<p>in <inline-formula><graphic file="1687-2770-2011-10-i146.gif"/></inline-formula> which is a perturbation of <inline-formula><graphic file="1687-2770-2011-10-i147.gif"/></inline-formula>. Writing <inline-formula><graphic file="1687-2770-2011-10-i148.gif"/></inline-formula>. This amounts to solve</p>
<p><display-formula><graphic file="1687-2770-2011-10-i149.gif"/></display-formula></p>
<p>We need to define some auxiliary weighted spaces:</p>
<p><b>Definition 6 </b><it>Let </it><inline-formula><graphic file="1687-2770-2011-10-i150.gif"/></inline-formula>, <it>k </it>&#8712; &#8477;, <it>&#946; </it>&#8712; (0, 1) <it>and &#957; </it>&#8712; &#8477;<it>, we define the H&#246;lder weighted space <inline-formula><graphic file="1687-2770-2011-10-i151.gif"/></inline-formula> as the set of functions <inline-formula><graphic file="1687-2770-2011-10-i152.gif"/></inline-formula> for which the following norm</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i153.gif"/></display-formula></p>
<p><it>is finite</it></p>
<p>For all <it>&#963; </it>&#8712; (0, <it>r</it><sub>0</sub>/2) and all <it>Y </it>= (<it>y</it><sub>1</sub>, ..., <it>y<sub>m</sub></it>) &#8712; &#937;<it><sup>m </sup></it>such that ||<it>X - Y </it>|| &#8804; <it>r</it><sub>0</sub>/2, where <it>X </it>= (<it>x</it><sub>1</sub>, ..., <it>x<sub>m</sub></it>), we denote by</p>
<p><display-formula><graphic file="1687-2770-2011-10-i154.gif"/></display-formula></p>
<p>the extension operator defined by <inline-formula><graphic file="1687-2770-2011-10-i155.gif"/></inline-formula> in <inline-formula><graphic file="1687-2770-2011-10-i156.gif"/></inline-formula></p>
<p><display-formula><graphic file="1687-2770-2011-10-i157.gif"/></display-formula></p>
<p>for each <it>i </it>= 1, ..., <it>m </it>and <inline-formula><graphic file="1687-2770-2011-10-i158.gif"/></inline-formula> in each <it>B</it><sub><it>&#963;</it>/2</sub>(<it>y<sub>i</sub></it>), where <inline-formula><graphic file="1687-2770-2011-10-i159.gif"/></inline-formula> is a cutoff function identically equal to 1 for <it>t </it>&#8805; 1 and identically equal to 0 for <it>t </it>&#8804; 1/2. It is easy to check that there exists a constant <it>c </it>= <it>c</it>(<it>&#957;</it>) <it>&gt; </it>0 only depending on <it>&#957; </it>such that</p>
<p><display-formula id="M35"><graphic file="1687-2770-2011-10-i160.gif"/></display-formula></p>
<p>We fix</p>
<p><display-formula><graphic file="1687-2770-2011-10-i161.gif"/></display-formula></p>
<p>and denote by <inline-formula><graphic file="1687-2770-2011-10-i162.gif"/></inline-formula> a right inverse of &#916; provided by Proposition 3 with <inline-formula><graphic file="1687-2770-2011-10-i163.gif"/></inline-formula>. Clearly, it is enough to find <inline-formula><graphic file="1687-2770-2011-10-i164.gif"/></inline-formula> solution of</p>
<p><display-formula id="M36"><graphic file="1687-2770-2011-10-i165.gif"/></display-formula></p>
<p>where</p>
<p><display-formula><graphic file="1687-2770-2011-10-i166.gif"/></display-formula></p>
<p>We denote by <inline-formula><graphic file="1687-2770-2011-10-i167.gif"/></inline-formula> the nonlinear operator which appears on the right hand side of Eq.(36). Given <it>&#954; </it>&gt; 0 (whose value will be fixed later on), we assume that the points <inline-formula><graphic file="1687-2770-2011-10-i168.gif"/></inline-formula>, the functions <inline-formula><graphic file="1687-2770-2011-10-i169.gif"/></inline-formula> and the parameters <inline-formula><graphic file="1687-2770-2011-10-i170.gif"/></inline-formula> to satisfy</p>
<p><display-formula id="M37"><graphic file="1687-2770-2011-10-i171.gif"/></display-formula></p>
<p><display-formula id="M38"><graphic file="1687-2770-2011-10-i172.gif"/></display-formula></p>
<p>and</p>
<p><display-formula id="M39"><graphic file="1687-2770-2011-10-i173.gif"/></display-formula></p>
<p>Then, the following result holds</p>
<p><b>Lemma 6 </b><it>Given &#954; &gt; </it>0, <it>there exist &#949;<sub>&#954; </sub>&gt; </it>0, <it>&#955;<sub>&#954; </sub>&gt; </it>0, <it>c<sub>&#954; </sub>&gt; </it>0 <it>and </it><inline-formula><graphic file="1687-2770-2011-10-i71.gif"/></inline-formula> <it>(depending on &#954;) such that for all &#949; </it>&#8712; (0, <it>&#949;<sub>&#954; </sub></it>)<it>, &#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>)</p>
<p><display-formula><graphic file="1687-2770-2011-10-i174.gif"/></display-formula></p>
<p><it>and</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i175.gif"/></display-formula></p>
<p><it>provided </it><inline-formula><graphic file="1687-2770-2011-10-i176.gif"/></inline-formula> <it>and satisfy </it><inline-formula><graphic file="1687-2770-2011-10-i177.gif"/></inline-formula>.</p>
<p><it>Proof: </it>Recall that <inline-formula><graphic file="1687-2770-2011-10-i178.gif"/></inline-formula>, we will estimate <inline-formula><graphic file="1687-2770-2011-10-i179.gif"/></inline-formula> in different subregions of <inline-formula><graphic file="1687-2770-2011-10-i180.gif"/></inline-formula>.</p>
<p>* In <inline-formula><graphic file="1687-2770-2011-10-i181.gif"/></inline-formula>, we have <inline-formula><graphic file="1687-2770-2011-10-i182.gif"/></inline-formula>, <inline-formula><graphic file="1687-2770-2011-10-i183.gif"/></inline-formula> and</p>
<p><display-formula id="M40"><graphic file="1687-2770-2011-10-i184.gif"/></display-formula></p>
<p>so that</p>
<p><display-formula><graphic file="1687-2770-2011-10-i185.gif"/></display-formula></p>
<p>Hence, for <it>&#957; </it>&#8712; (- 1, 0) and for <inline-formula><graphic file="1687-2770-2011-10-i186.gif"/></inline-formula> small enough, we get</p>
<p><display-formula><graphic file="1687-2770-2011-10-i187.gif"/></display-formula></p>
<p>* In <inline-formula><graphic file="1687-2770-2011-10-i188.gif"/></inline-formula>, we have <inline-formula><graphic file="1687-2770-2011-10-i182.gif"/></inline-formula> and <inline-formula><graphic file="1687-2770-2011-10-i183.gif"/></inline-formula>. Thus</p>
<p><display-formula><graphic file="1687-2770-2011-10-i189.gif"/></display-formula></p>
<p>So, for <it>&#957; </it>&#8712; (- 1, 0), we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i190.gif"/></display-formula></p>
<p>* In <inline-formula><graphic file="1687-2770-2011-10-i191.gif"/></inline-formula>, using the estimat (40), then we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i192.gif"/></display-formula></p>
<p>where</p>
<p><display-formula><graphic file="1687-2770-2011-10-i193.gif"/></display-formula></p>
<p>Then</p>
<p><display-formula><graphic file="1687-2770-2011-10-i194.gif"/></display-formula></p>
<p>So,</p>
<p><display-formula id="M41"><graphic file="1687-2770-2011-10-i195.gif"/></display-formula></p>
<p>Making use of Proposition 3 together with (34), we conclude that</p>
<p><display-formula id="M42"><graphic file="1687-2770-2011-10-i196.gif"/></display-formula></p>
<p>For the proof of the second estimate, let <inline-formula><graphic file="1687-2770-2011-10-i197.gif"/></inline-formula> and <inline-formula><graphic file="1687-2770-2011-10-i198.gif"/></inline-formula> satisfying <inline-formula><graphic file="1687-2770-2011-10-i199.gif"/></inline-formula> for <it>i </it>= 1,2, we have</p>
<p><display-formula><graphic file="1687-2770-2011-10-i200.gif"/></display-formula></p>
<p>Then for <it>&#947; </it>&#8712; (0,1), we get</p>
<p><display-formula><graphic file="1687-2770-2011-10-i201.gif"/></display-formula></p>
<p>So, for <inline-formula><graphic file="1687-2770-2011-10-i186.gif"/></inline-formula> small enough and using the estimate (35), there exist <inline-formula><graphic file="1687-2770-2011-10-i202.gif"/></inline-formula> (depending on <it>&#954; </it>), such that:</p>
<p><display-formula id="M43"><graphic file="1687-2770-2011-10-i203.gif"/></display-formula></p>
<p>&#9633;</p>
<p>Reducing <it>&#955;<sub>&#954; </sub></it>&gt; 0 and <it>&#949; </it><sub><it>&#954; </it></sub>&gt; 0 if necessary, we can assume that, <inline-formula><graphic file="1687-2770-2011-10-i124.gif"/></inline-formula> for all <it>&#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>) and <it>&#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>). Then, (42) and (43) are enough to show that <inline-formula><graphic file="1687-2770-2011-10-i204.gif"/></inline-formula> is a contraction from <inline-formula><graphic file="1687-2770-2011-10-i205.gif"/></inline-formula> into itself and hence has a unique fixed point <inline-formula><graphic file="1687-2770-2011-10-i206.gif"/></inline-formula> in this set. This fixed point is solution of (35). We summarize this in the following</p>
<p><b>Proposition 5 </b><it>Given &#954; &gt; </it>0<it>, there exists &#949;<sub>&#954; </sub></it>&gt; 0 <it>and &#955;<sub>&#954; </sub></it>&gt; 0 <it>(depending on &#954;) such that for all &#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>) <it>and &#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>)<it>, for all set of parameter </it><inline-formula><graphic file="1687-2770-2011-10-i186.gif"/></inline-formula> <it>satisfying (39) and function <inline-formula><graphic file="1687-2770-2011-10-i207.gif"/></inline-formula> satisfying (26), there exists a unique <inline-formula><graphic file="1687-2770-2011-10-i208.gif"/></inline-formula> solution of (36) such that</it></p>
<p><display-formula><graphic file="1687-2770-2011-10-i209.gif"/></display-formula></p>
<p>As in the previous section, observe that the function <inline-formula><graphic file="1687-2770-2011-10-i210.gif"/></inline-formula> being obtained as a fixed point for contraction mapping, depends smoothly on the parameters <inline-formula><graphic file="1687-2770-2011-10-i211.gif"/></inline-formula> and the points <inline-formula><graphic file="1687-2770-2011-10-i212.gif"/></inline-formula>.</p>
</sec>
<sec><st><p>5 The nonlinear Cauchy-data matching</p></st>
<p>Keeping the notations of the previous sections, we gather the results of Proposition 4 and 5. Assume that <inline-formula><graphic file="1687-2770-2011-10-i213.gif"/></inline-formula> &#8712; &#937;<it><sup>m </sup></it>are given close to <b>x </b>:= (<it>x</it><sub>1</sub>, ..., <it>x<sub>m</sub></it>) and satisfy (37). Assume also that <it>&#964; </it>:= (<it>&#964;</it><sub>1</sub>, ..., <it>&#964;<sub>m</sub></it>) &#8712; [<it>&#964; <sub>-</sub></it>, <it>&#964; </it><sup>+</sup>]<it><sup>m </sup></it>&#8834; (0, &#8734;)<it><sup>m </sup></it>are given (the values of <it>&#964;</it><sub>- </sub>and <it>&#964; </it><sup>+ </sup>will be fixed shortly). First, we consider some set of boundary data <inline-formula><graphic file="1687-2770-2011-10-i214.gif"/></inline-formula> satisfying (24). We set</p>
<p><display-formula><graphic file="1687-2770-2011-10-i215.gif"/></display-formula></p>
<p>According to the result of Proposition 4, we can find <inline-formula><graphic file="1687-2770-2011-10-i216.gif"/></inline-formula> a solution of</p>
<p><display-formula id="M44"><graphic file="1687-2770-2011-10-i217.gif"/></display-formula></p>
<p>in each <inline-formula><graphic file="1687-2770-2011-10-i218.gif"/></inline-formula> that can be decomposed as</p>
<p><display-formula><graphic file="1687-2770-2011-10-i219.gif"/></display-formula></p>
<p>where the function <inline-formula><graphic file="1687-2770-2011-10-i220.gif"/></inline-formula> satisfies</p>
<p><display-formula id="M45"><graphic file="1687-2770-2011-10-i221.gif"/></display-formula></p>
<p>Similarly, given some boundary data <inline-formula><graphic file="1687-2770-2011-10-i222.gif"/></inline-formula> satisfying (26), some parameters <inline-formula><graphic file="1687-2770-2011-10-i223.gif"/></inline-formula> satisfying (38), provide <it>&#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>) and <it>&#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>), we use the result of Proposition 5, to find a solution <it>v<sub>ext </sub></it>of (43) which can be decomposed as</p>
<p><display-formula><graphic file="1687-2770-2011-10-i224.gif"/></display-formula></p>
<p>in <inline-formula><graphic file="1687-2770-2011-10-i225.gif"/></inline-formula> where, the function <inline-formula><graphic file="1687-2770-2011-10-i226.gif"/></inline-formula> satisfies</p>
<p><display-formula id="M46"><graphic file="1687-2770-2011-10-i227.gif"/></display-formula></p>
<p>It remains to determine the parameters and the functions in such a way that the function which is equal to <inline-formula><graphic file="1687-2770-2011-10-i228.gif"/></inline-formula> in <inline-formula><graphic file="1687-2770-2011-10-i229.gif"/></inline-formula> and that is equal to <it>v</it><sub>ext </sub>in <inline-formula><graphic file="1687-2770-2011-10-i230.gif"/></inline-formula> is a smooth function. This amounts to find the boundary data and the parameters so that, for each <it>i </it>= 1 ..., <it>m</it></p>
<p><display-formula id="M47"><graphic file="1687-2770-2011-10-i231.gif"/></display-formula></p>
<p>on <inline-formula><graphic file="1687-2770-2011-10-i232.gif"/></inline-formula>. Assuming we have already done so, this provides for each <it>&#949; </it>and <it>&#955; </it>small enough a function <inline-formula><graphic file="1687-2770-2011-10-i233.gif"/></inline-formula> (which is obtained by patching together the functions <inline-formula><graphic file="1687-2770-2011-10-i228.gif"/></inline-formula> and the function <it>v</it><sub>ext</sub>) solution of -&#916;<it>v </it>- <it>&#955; </it>|&#8711;<it>v</it>|<sup>2 </sup>= <it>&#961;</it><sup>2 </sup>(<it>e<sup>v </sup></it>+ <it>e<sup>&#947;v</sup></it>) and elliptic regularity theory implies that this solution is in fact smooth. This will complete the proof of our result since, as <it>&#949; </it>and <it>&#955; </it>tend to 0, the sequence of solutions we have obtained satisfies the required properties, namely, away from the points <it>x<sub>i </sub></it>the sequence <it>v</it><sub><it>&#949;</it>,<it>&#955; </it></sub>converges to <inline-formula><graphic file="1687-2770-2011-10-i234.gif"/></inline-formula>. Before we proceed, the following remarks are due. First, it will be convenient to observe that the function <inline-formula><graphic file="1687-2770-2011-10-i235.gif"/></inline-formula> can be expanded as</p>
<p><display-formula id="M48"><graphic file="1687-2770-2011-10-i236.gif"/></display-formula></p>
<p>near <inline-formula><graphic file="1687-2770-2011-10-i237.gif"/></inline-formula>. The function</p>
<p><display-formula><graphic file="1687-2770-2011-10-i238.gif"/></display-formula></p>
<p>which appear in the expression of <it>v<sub>ext </sub></it>can be expanded as</p>
<p><display-formula id="M49"><graphic file="1687-2770-2011-10-i239.gif"/></display-formula></p>
<p>Near <inline-formula><graphic file="1687-2770-2011-10-i232.gif"/></inline-formula>. Here, we have defined</p>
<p><display-formula><graphic file="1687-2770-2011-10-i240.gif"/></display-formula></p>
<p>Thus for <it>x </it>near <inline-formula><graphic file="1687-2770-2011-10-i237.gif"/></inline-formula>, we have</p>
<p><display-formula id="M50"><graphic file="1687-2770-2011-10-i241.gif"/></display-formula></p>
<p>where <inline-formula><graphic file="1687-2770-2011-10-i242.gif"/></inline-formula>.</p>
<p>Next, in (47), all functions are defined on <inline-formula><graphic file="1687-2770-2011-10-i232.gif"/></inline-formula>, but it will be convenient to solve the following equations</p>
<p><display-formula id="M51"><graphic file="1687-2770-2011-10-i243.gif"/></display-formula></p>
<p>on <it>S</it><sup>1</sup>. Here, all functions are considered as functions of <it>y </it>&#8712; <it>S</it><sup>1 </sup>and we have simply used the change of variables <inline-formula><graphic file="1687-2770-2011-10-i244.gif"/></inline-formula> to parameterize <inline-formula><graphic file="1687-2770-2011-10-i232.gif"/></inline-formula>.</p>
<p>Since the boundary data, we have chosen satisfy (24) and (26), we can decompose</p>
<p><display-formula><graphic file="1687-2770-2011-10-i245.gif"/></display-formula></p>
<p>where <inline-formula><graphic file="1687-2770-2011-10-i246.gif"/></inline-formula> are constant functions on <it>S</it><sup>1</sup>, <inline-formula><graphic file="1687-2770-2011-10-i247.gif"/></inline-formula> belong to <inline-formula><graphic file="1687-2770-2011-10-i248.gif"/></inline-formula> and where <inline-formula><graphic file="1687-2770-2011-10-i249.gif"/></inline-formula> are <it>L</it><sup>2</sup>(<it>S</it><sup>1</sup>) orthogonal to <inline-formula><graphic file="1687-2770-2011-10-i250.gif"/></inline-formula> and <inline-formula><graphic file="1687-2770-2011-10-i251.gif"/></inline-formula>. Projecting the equations (51) over <inline-formula><graphic file="1687-2770-2011-10-i250.gif"/></inline-formula> will yield the system</p>
<p><display-formula id="M52"><graphic file="1687-2770-2011-10-i252.gif"/></display-formula></p>
<p>Let us comment briefly on how these equations are obtained. They simply come from (51) when expansions (48) and (49) are used, together with the expression of <it>H<sup>i </sup></it>and <it>H<sup>e </sup></it>given in Lemma 2 and Lemma 3, and also the estimates (45) and (46). The system (52) can be readily simplified into</p>
<p><display-formula><graphic file="1687-2770-2011-10-i253.gif"/></display-formula></p>
<p>We are now in a position to define <it>&#964; <sub>- </sub></it>and <it>&#964; </it><sup>+ </sup>since, according to the above, as <it>&#949; </it>and <it>&#955; </it>tend to 0 we expect that <inline-formula><graphic file="1687-2770-2011-10-i254.gif"/></inline-formula> will converge to <it>x<sub>i </sub></it>and that <it>&#964;<sub>i </sub></it>will converge to <inline-formula><graphic file="1687-2770-2011-10-i255.gif"/></inline-formula> satisfying</p>
<p><display-formula><graphic file="1687-2770-2011-10-i256.gif"/></display-formula></p>
<p>and hence, it is enough to choose <it>&#964; <sub>- </sub></it>and <it>&#964; </it><sup>+ </sup>in such a way that</p>
<p><display-formula><graphic file="1687-2770-2011-10-i257.gif"/></display-formula></p>
<p>We now consider the <it>L</it><sup>2</sup>-projection of (51) over <inline-formula><graphic file="1687-2770-2011-10-i251.gif"/></inline-formula>. Given a smooth function <it>f </it>defined in &#937;, we identify its gradient <inline-formula><graphic file="1687-2770-2011-10-i258.gif"/></inline-formula> with the element of <inline-formula><graphic file="1687-2770-2011-10-i251.gif"/></inline-formula></p>
<p><display-formula><graphic file="1687-2770-2011-10-i259.gif"/></display-formula></p>
<p>With these notations in mind, we obtain the equations</p>
<p><display-formula id="M53"><graphic file="1687-2770-2011-10-i260.gif"/></display-formula></p>
<p>Finally, we consider the <it>L</it><sup>2</sup>-projection onto <it>L</it><sup>2</sup>(<it>S</it><sup>1</sup>)<sup>&#8869;</sup>. This yields the system</p>
<p><display-formula id="M54"><graphic file="1687-2770-2011-10-i261.gif"/></display-formula></p>
<p>Thanks to the result of Lemma 4, this last system can be re-written as</p>
<p><display-formula><graphic file="1687-2770-2011-10-i262.gif"/></display-formula></p>
<p>If we define the parameters <b>t </b>= (<it>t<sub>i</sub></it>) &#8712; &#8477;<it><sup>m </sup></it>by</p>
<p><display-formula><graphic file="1687-2770-2011-10-i263.gif"/></display-formula></p>
<p>then, the system we have to solve reads</p>
<p><display-formula id="M55"><graphic file="1687-2770-2011-10-i264.gif"/></display-formula></p>
<p>where as usual, the terms <inline-formula><graphic file="1687-2770-2011-10-i265.gif"/></inline-formula> depend nonlinearly on all the variables on the left side, but is bounded (in the appropriate norm) by a constant (independent of <it>&#949; </it>and <it>&#955;</it>) time <inline-formula><graphic file="1687-2770-2011-10-i266.gif"/></inline-formula>, provide <it>&#949; </it>&#8712; (0, <it>&#949;<sub>&#954;</sub></it>) and <it>&#955; </it>&#8712; (0, <it>&#955;<sub>&#954;</sub></it>). Then, the nonlinear mapping which appears on the right-hand side of (55) is continuous and compact. In addition, reducing <it>&#949;<sub>&#954; </sub></it>and <it>&#955;<sub>&#954; </sub></it>if necessary, this nonlinear mapping sends the ball of radius <inline-formula><graphic file="1687-2770-2011-10-i267.gif"/></inline-formula> (for the natural product norm) into itself, provided <it>&#954; </it>is fixed large enough. Applying Schauder's fixed Theorem in the ball of radius <inline-formula><graphic file="1687-2770-2011-10-i267.gif"/></inline-formula> in the product space where the entries live yields the existence of a solution of Eq. (55) and this completes the proof of our Theorem 1. &#9633;</p>
</sec>
<sec><st><p>Competing interests</p></st>
<p>The authors declare that they have no competing interests.</p>
</sec>
<sec><st><p>Authors' contribution</p></st>
<p>The authors declare that the work was realized in collaboration with same responsibility. All authors read and approved the final manuscript.</p>
</sec>
</bdy>
<bm>
<ack><sec><st><p>Acknowledgements</p></st>
<p>The authors extend their appreciation to the Deanship of Scientific Research at King Saud University for funding the work through the research group project No RGP-VPP-087.</p>
</sec>
</ack>
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